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pian0forte
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Homework Statement
Find the general solution, y
2ty dy/dt = 3y^2 - t^2
Homework Equations
The Attempt at a Solution
I probably have to separate the equation and get y's one side in order to solve, but I'm stuck as to how to separate it. I tried letting u = y/t, so then
du/dt = (t dy/dt - y)/(t^2)
then dy/dt = t du/dt + u , so I plugged it back into the equation?
t du/dt + u = (3y^2 - t^2)/(2ty)
t du/dt + u = (3/2)u - (1/2u)
I can separate this into:
(u/(u^2-1)) du/dt = 1/2t
Am I on the right track?
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