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Hi, I have an exercise whose solution seems too simple; please double-check my work:
We have a product manifold MxN, and want to show that if w is a k-form in M and
w' is a k-form in N, then ##(w \bigoplus w')(X,Y)## , for vector fields X,Y in M,N respectively,
is a k-form in MxN.
I am assuming k=1 , and then we can generalize. My proof:
We start with (the isomorphism):
##(T_{(m,n)}(M\times N) = (T_m M \bigoplus T_n N)##,
Then, dualizing both sides:##(T_{(m,n)} (M \times N))^* =(T_m M \bigoplus T_n N)^*##.
We then use that ##(A \bigoplus B)^*= A^* \bigoplus B^*## , to get :
##(T_{(m,n)} (M \times N))^* = (T_m M )^*\bigoplus (T_n N)^* ##.
Is that all there is to it?
We have a product manifold MxN, and want to show that if w is a k-form in M and
w' is a k-form in N, then ##(w \bigoplus w')(X,Y)## , for vector fields X,Y in M,N respectively,
is a k-form in MxN.
I am assuming k=1 , and then we can generalize. My proof:
We start with (the isomorphism):
##(T_{(m,n)}(M\times N) = (T_m M \bigoplus T_n N)##,
Then, dualizing both sides:##(T_{(m,n)} (M \times N))^* =(T_m M \bigoplus T_n N)^*##.
We then use that ##(A \bigoplus B)^*= A^* \bigoplus B^*## , to get :
##(T_{(m,n)} (M \times N))^* = (T_m M )^*\bigoplus (T_n N)^* ##.
Is that all there is to it?
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