Differentiate f(x)=2x^(2/3)(3-4x^(1/3))

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To differentiate the function f(x) = [2x^(2/3)][3-4x^(1/3)], the product rule is applied correctly, where f' = g'h + gh'. The initial attempt yielded f'(x) = (4/3)(x^(-1/3))(3-4x^(1/3)) + (1/3)(-4)(x^(-2/3)), but an error was identified in not multiplying the second term by 2x^(2/3). The correct differentiation requires careful application of the product rule to avoid mistakes. Ultimately, the discussion emphasizes the importance of correctly applying differentiation rules to achieve accurate results.
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Homework Statement


differentiate f(x) = [2x^(2/3)][3-4x^(1/3)]


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The Attempt at a Solution


f'(x) = (4/3)(x^(-1/3))(3-4x^(1/3)) + (1/3)(-4)(x^(-2/3))
= 4x^(-1/3)-(16/3)-((4/3)(x^(-2/3)))
= (4/x^(1/3))-(16/3)-(4/3(x^(-2/3)))
I'm pretty sure I've made a mistake, but I can't find it.
 
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Remember, the product rule is defined as f' = g'h + gh'. When you used the product rule, you forgot to multiply the second term by 2x^{2/3}.
 
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