Differentiate y component of velocity wrt time

In summary, the conversation discusses the y-component of velocity in projectile motion, specifically how it is differentiated with respect to time and if it equals -g. The orientation of the coordinate system may affect the sign, but for the purposes of the question, it is assumed to be the usual upward direction.
  • #1
ZedCar
354
1

Homework Statement


A ball is thrown with an angle of 45 degrees to the horizontal by a person standing on the ground.

The y-component of the velocity of ball in projectile motion is differentiated with respect to time. i.e. dv/dt of the y-component of velocity.

Homework Equations


The Attempt at a Solution



Does this equal -g? (not g)
 
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  • #2
Hi ZedCar! :smile:
ZedCar said:
…. i.e. dv/dt of the y-component of velocity.

you mean,

d/dt of the y-component of velocity

or the y-component of dv/dt

or d/dt of vy :wink:
Does this equal -g? (not g)

yes :smile:
 
  • #3
But isn't the sign supposed to depend on the orientation of the coordinate system?
 
  • #4
failexam said:
But isn't the sign supposed to depend on the orientation of the coordinate system?

yes, but i think we can safely assume that the y direction mentioned in the question is the usual upward one :smile:
 
  • #5


Yes, the y-component of velocity in projectile motion can be represented as vy = v0sinθ - gt, where v0 is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. Therefore, differentiating with respect to time gives dv/dt = -g. This represents the acceleration in the y-direction due to gravity.
 

FAQ: Differentiate y component of velocity wrt time

What is the meaning of "differentiate y component of velocity wrt time"?

"Differentiate y component of velocity wrt time" refers to finding the rate of change of the y component of velocity with respect to time. In other words, it is calculating how fast the y component of velocity is changing over time.

Why is it important to differentiate the y component of velocity wrt time?

It is important to differentiate the y component of velocity wrt time because it allows us to understand the acceleration in the y direction. This information is crucial in analyzing the motion of objects and predicting their future positions.

How do you differentiate the y component of velocity wrt time?

To differentiate the y component of velocity wrt time, we use the derivative formula: dy/dt, where y represents the y component of velocity and t represents time. This formula tells us the instantaneous rate of change of the y component of velocity at any given moment.

Can you give an example of differentiating the y component of velocity wrt time?

Sure, for example, if an object is moving in a straight line with a y component of velocity given by v = 2t + 5, we can differentiate this to find the acceleration in the y direction. The derivative of v with respect to t is dv/dt = 2, meaning the acceleration in the y direction is constant at 2 m/s^2.

Are there any real-life applications of differentiating the y component of velocity wrt time?

Yes, there are many real-life applications of differentiating the y component of velocity wrt time. For example, it is used in physics and engineering to analyze the motion of objects, in economics to calculate marginal costs and revenues, and in medicine to understand the changing rates of biological processes over time.

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