Differentiating composite functions

[Dough]

i have bee strugglignwith thes ethree questions for some time now done the 1st one like 8 times :S
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rewrite each of the following in the form y=u^n or y=ku^n, and then differntiate
1) y = ((1 + x^1/2)/ x^2/3))^3
i started this by doing writing it out as y = [(1+x^1/2)(x^-2/3)]^3
then i went did dy/dx = 3[(1+x^1/2)(x^-2/3)]^2[(1/2x^-1/2)(x^-2/3) + (1+x)(-2/3x^-5/3)]
after simplifying soem i get... 3(1+x^1/2)^2(x^-4/3)(1/2x^1/3-2x^-5/3-2/3x^-2/3)
ok then i get
3x^-4/3(1+2x^1/2 + x)(1/2x^1/3-2x^-5/3-2/3x^-2/3)
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Differentiate each function. Express your answer in a simplified factored form.
2) f(x) = (x+4)^3 (x-3)6
3) g(x) = (2x-1)^4 (2-3x)^4
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Btw the questions are from the Harcourt Mathematics 12, Advanced Functions & Introductory Calculus, Chapter 4.6 questions 3i, 4a, 4c
the answers ar in teh abck and i haven't even ocme close to the right ones :(
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Thanks in advance
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Also is there an easier way to type this up?

 

[Aaron Bex]

i mean the math formulas

2) f(x) = (x + 4)^3(x - 3)^6
f'(x) = 3(x + 4)^2 (x - 3)^6 + 6(x + 4)^3 (x - 3)^5(-1)
f'(x) = 3(x + 4)^2 (x - 3)^6 - 6(x + 4)^3 (x - 3)^5

3) g(x) = (2x - 1)^4 (2 - 3x)^4
g'(x) = 4(2x - 1)^3 (2 - 3x)^4 + 4(2x - 1)^4(2 - 3x)^3(-3)
g'(x) = 4(2x - 1)^3 (2 - 3x)^4 - 12(2x - 1)^4(2 - 3x)^3