Differentiating thermodynamic coefficients

In summary: I can't do that. Differentiating with respect to temperature and pressure at the same time is confusing and makes it difficult to see what is going on.
  • #1
Nikitin
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Homework Statement


In oppgave 1 a) I am supposed to show that the given equality is true (namely that the isoterm compressibility coefficient partial-differentiated with regards to temperature = isobar coefficient differentiated with regards to pressure multiplied by minus one).

http://web.phys.ntnu.no/~stovneng/TFY4165_2014/oving2.pdf

The Attempt at a Solution

I can naturally see that the way to attack this problem is to simply carry out the differentiations, but how does it make sense to partially differentiate ##\alpha_V## with regards to ##p## when ##\alpha_V## assumes constant pressure? And besides, ##\alpha_V## measures the change of relative volume as a function of ##T##, yet constant temperature is assumed for ##\frac{\partial \alpha_V}{\partial p}##? It's a similar problem with the differentiating the isoterm coefficient with regards to temperature while keeping pressure constant..
 
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  • #2
Not strong in Norwegian. alpha_v may be defined at constant pressure, that doesn't mean its value is independent of the pressure!
 
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  • #3
Okay, but alpha_v is the change of relative volume with regards to temperature, yet ##\frac{\partial \alpha_V}{\partial p}## assumes constant temperature? How does it make sense to calculate how ##\alpha_V## (which is a measure of how the volume varies with regards to temperature) varies while the temperature is constant?
 
  • #4
##\alpha_V## is a function of both temperature and pressure. Unfortunately, many, if not most, texts on thermodynamics do a very bad job at explaining functional dependencies among all the things they operate with. The unconventional notation ##\left({\partial X \over \partial Y}\right)_{Z}## is my personal anti-favorite, because in my experience very few students understand what it really signifies. Just for the record, it means that ##X## is considered to be a function of ##Y## and ##Z##, and is differentiated with respect to ##Y##. The usually added bit that ##Z## is held constant is redundant because that follows from the definition of partial differentiation. I suspect it is not only redundant, but is severely confusing, because the obvious redundancy makes the inexperienced reader wonder what really is going on.
 
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  • #5
Please write down your defining equations for αV and κT. Once you get a look at these, you will see immediately how to prove what you are trying to prove.
 

FAQ: Differentiating thermodynamic coefficients

What are thermodynamic coefficients?

Thermodynamic coefficients are mathematical parameters that describe how different variables, such as temperature, pressure, and volume, are related in a thermodynamic system. They are used to characterize the behavior and properties of materials and substances under various conditions.

How are thermodynamic coefficients determined?

Thermodynamic coefficients are typically determined through various experimental techniques, such as calorimetry and thermal analysis, or through theoretical calculations based on thermodynamic models. These coefficients can also be extracted from empirical data using regression analysis.

What is the significance of differentiating thermodynamic coefficients?

Differentiating thermodynamic coefficients is important for understanding the relationships between different thermodynamic variables and how they affect the behavior of a system. This can help in predicting and controlling the properties and behavior of materials in various processes and applications.

How do thermodynamic coefficients change with temperature and pressure?

Thermodynamic coefficients can vary significantly with changes in temperature and pressure. Generally, as temperature increases, these coefficients also increase, while increasing pressure can have varying effects depending on the specific coefficient and substance. These changes in coefficients are important for understanding the behavior of a system under different conditions.

Can thermodynamic coefficients be negative?

Yes, thermodynamic coefficients can have negative values. This typically occurs when there is an inverse relationship between the two variables being studied, such as temperature and entropy. A negative coefficient indicates that as one variable increases, the other decreases, and vice versa.

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