Differentiating x(t): Solutions & Examples

  • Thread starter JakePearson
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Even if it doesn't, other people will have a difficult time following what you're trying to say.2) Differentiate x(t) = 1 / (At3 + B)x(t) = (At3 + B) -1x'(t) = -1 (At3 + B)-2 (3At2)I'm not sure what you did, so I'm starting from the beginning. First, write the equation for the derivative x'(t). You'll need to use the quotient rule.x'(t) = [(At3 + B)-1 (A(3t2)) - (At3 + B) (3A(3t3))]/(At3 + B)2
  • #1
JakePearson
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0
1)
Differentiate x(t) = pi / t2
pi x(t) = t-2
= pi (t-2)
= -2pi t-3

2)
Differentiate x(t) = 1 / (At3 + B)
= (At3 + B)-2 x (2At2)
= (-2At2) / (At3 + B)

3)
Differentiate x(t) = [A sqrt(t+B)]4
= [A (t+B)1/2]4
= A4(t + B)2
= 2A4(t + B)

4)
The nebraska board of grain are designing new portable grain silos. they have enough sheet material to make 2000 cylinderical containers, each of fixed surface area 54m2 (this includesthe cylinder ends). calculate in terms of pi the maximum volume of grain that could be stored in total?

my answer is = for 1 container V is 30.46m3, so for 2000 containers (30.46 x 2000) = 60920m3 is this correct

5)
The height h(x) in meters above the ground of a parachute varies with her horizontal distance x in meters from a landing target on the ground as h(x) = 50sin-1 (0.1x). What is the rate of change of h with respect to x = 6m?

my answer is (25 / 4) is this correct
 
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  • #2
HI JakePearson! :smile:

First, you must begin your proofs with "dx/dt =" (or "x'(t) = ").

(and have a pi: π and a square-root: √ :wink:)
JakePearson said:
1)
Differentiate x(t) = pi / t2
pi x(t) = t-2
= pi (t-2)
= -2pi t-3

ok (apart from "pi x(t) = t-2")
2)
Differentiate x(t) = 1 / (At3 + B)
= (At3 + B)-2 x (2At2)
= (-2At2) / (At3 + B)

No, 2At2 is wrong, and the last line is also wrong.
3)
Differentiate x(t) = [A sqrt(t+B)]4
= [A (t+B)1/2]4
= A4(t + B)2
= 2A4(t + B)

ok, except see my original comment.
4) …

5) …

uhh? :redface: show your calclulations!
 
  • #3
1) is OK

2) is wrong ... I assume there is a - sign error of copying, since it appears later. But there is another error.

3) is OK

4) is at least incomplete. To tell if if it right I would have to do it myself (rather than checking that you have done it right.

5) correct answer, but if "showing work" is required it is incomplete
 
  • #4
1)
Differentiate x(t) = pi / t2
pi x(t) = t-2
= pi (t-2)
= -2pi t-3
You arrived at the correct answer, but the work you show is incorrect. To expand on what tiny-tim said, your first line should be the function you're going to differentiate, and the second should start with dx/dt or x'(t).

Your second line is incorrect. Apparently you multiplied both sides by [itex]\pi[/itex] (which would leave [itex]\pi^2[/itex] on the right side. The expression in the third line is not equal to the previous line. What you omitted showing is that you took the derivative.

Here's how your work should look:
x(t) = [itex]\pi[/itex] / t2 = [itex]\pi[/itex] t-2
x'(t) = -2 [itex]\pi[/itex] t-3

It's very important to distinguish between the equation for the function you're differentiating and the equation for the derivative. If you mix them up into one big, amorphous glop, there will come a time -- I GUARANTEE IT--that it will come along and bite you in the butt.
 

FAQ: Differentiating x(t): Solutions & Examples

What is the purpose of differentiating x(t)?

Differentiating x(t) is a mathematical process used to find the rate of change of a function with respect to its independent variable, t. It helps us to understand how the function is changing over time and can be applied in various fields such as physics, engineering, and economics.

What are the basic rules for differentiating x(t)?

The basic rules for differentiating x(t) are the power rule, product rule, quotient rule, and chain rule. The power rule states that the derivative of a function raised to a power is equal to the power multiplied by the function raised to the power minus one. The product rule states that the derivative of a product of two functions is equal to the first function times the derivative of the second function plus the second function times the derivative of the first function. The quotient rule states that the derivative of a quotient of two functions is equal to the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator. The chain rule states that the derivative of a composite function is equal to the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.

How can differentiating x(t) be applied in real-world scenarios?

Differentiating x(t) can be applied in various real-world scenarios, such as calculating velocity and acceleration of an object in motion, finding the optimal solution in economics, and analyzing the growth of populations in biology. It is also used in engineering to determine the rate of change of physical quantities, such as electric current and voltage in electrical circuits.

What are some common mistakes to avoid when differentiating x(t)?

Some common mistakes to avoid when differentiating x(t) include forgetting to use the chain rule when differentiating composite functions, not applying the power rule correctly, and making errors in basic algebraic manipulations. It is essential to double-check the steps and take your time to avoid making mistakes.

Can differentiating x(t) be used to find the maximum or minimum values of a function?

Yes, differentiating x(t) can be used to find the maximum or minimum values of a function. The maximum or minimum points of a function occur when the derivative of the function is equal to zero or does not exist. By setting the derivative of the function equal to zero and solving for the independent variable, we can find the maximum or minimum values.

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