- #1
The riddler
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1. Hello everyone, my problem is with differentation. It seems to be quite simple but i can't understand it. Its basically find dy/dx of this equation:
y=4-1/x
2. The only relevant equation is dy/dx
3. I know how to differentate the equation to get y'=4-x-1 but i don't know how to get from there to dy/dx. To be honest I am not really sure what dy/dx is. I have been told the answer is dy/dx=x-2. Can someone please give me a clear explanation to what dy/dx means and explain to me how i get from the y' equation to dy/dx. Thanks for any replies :)
y=4-1/x
2. The only relevant equation is dy/dx
3. I know how to differentate the equation to get y'=4-x-1 but i don't know how to get from there to dy/dx. To be honest I am not really sure what dy/dx is. I have been told the answer is dy/dx=x-2. Can someone please give me a clear explanation to what dy/dx means and explain to me how i get from the y' equation to dy/dx. Thanks for any replies :)
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