- #1
Patjamet
- 6
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Just wondering if I have done this correctly?
Differentiate:
[tex]x^{sin3x}[/tex]
[tex]x^{sin3x}=e^{sin(3x)ln(x)[/tex]
Employing chain rule.
[tex]y=e^{u}[/tex]
[tex]u=sin(3x)ln(x)[/tex]
[tex]dy/dx = e^{u}\times(sin(3x)/x + 3ln(x)cos(3x))[/tex]
Final Solution? =
[tex]dy/dx = e^{sin(3x)ln(x)}\times(sin(3x)/x + 3ln(x)cos(3x))[/tex]
Homework Statement
Differentiate:
[tex]x^{sin3x}[/tex]
The Attempt at a Solution
[tex]x^{sin3x}=e^{sin(3x)ln(x)[/tex]
Employing chain rule.
[tex]y=e^{u}[/tex]
[tex]u=sin(3x)ln(x)[/tex]
[tex]dy/dx = e^{u}\times(sin(3x)/x + 3ln(x)cos(3x))[/tex]
Final Solution? =
[tex]dy/dx = e^{sin(3x)ln(x)}\times(sin(3x)/x + 3ln(x)cos(3x))[/tex]