- #1
Hawksteinman
- 59
- 23
I was thinking and came up with this. I know it's wrong but can't find the mistake :(
dy/dx sin(x) = cos(x)
dy/dx sin(kx) = kcos(kx)
So dy/dx sin(3x) = 3cos(3x)
Now let Y = 3x
dy/dx sin(Y) = cos(Y) = cos(3x)
3cos(3x) = cos(3x)
3 = 1
Where is the mistake?
dy/dx sin(x) = cos(x)
dy/dx sin(kx) = kcos(kx)
So dy/dx sin(3x) = 3cos(3x)
Now let Y = 3x
dy/dx sin(Y) = cos(Y) = cos(3x)
3cos(3x) = cos(3x)
3 = 1
Where is the mistake?