Differentiation, Product Rule 3-terms

In summary, the conversation discusses finding the derivative of the function f(x) = (2x-1)(3x-2)(5x+1) by using the product rule. The attempt at a solution involves breaking down the function into two parts, f and g, and then applying the product rule to find the derivative. After correcting a missing bracket, the final answer is validated by expanding and simplifying the expression. The summary also mentions the possibility of making the jump to finding the derivative of a function with more than two factors.
  • #1
RaptorsFan
12
0

Homework Statement



f(x) = (2x-1)(3x-2)(5x+1) d/dx = ?

Note that I am letting (2x-1)(3x-2) = f and 5x+1 = g

Homework Equations



d/dx (fg) = f d/dx g + g d/dx f

The Attempt at a Solution



d/dx y = (2x-1)(3x-2)d/dx(5x+1)+(5x+1)d/dx((2x-1)(3x-2))

= (2x-1)(3x-2)(5)+ (5x+1)(2x-1)d/dx(3x-2)+(3x-2)d/dx(2x-1)
= 5(2x-1)(3x-2) + 3(5x+1)(2x+1) + 2(3x-2)

Can someone validate this answer for me?
 
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  • #2
RaptorsFan said:

Homework Statement



f(x) = (2x-1)(3x-2)(5x+1) d/dx = ?

Note that I am letting (2x-1)(3x-2) = f and 5x+1 = g

Homework Equations



d/dx (fg) = f d/dx g + g d/dx f

The Attempt at a Solution



d/dx y = (2x-1)(3x-2)d/dx(5x+1)+(5x+1)d/dx((2x-1)(3x-2))

= (2x-1)(3x-2)(5)+ (5x+1)(2x-1)d/dx(3x-2)+(3x-2)d/dx(2x-1)
missed a bracket here, should be
= (2x-1)(3x-2)(5)+ (5x+1)[(2x-1)d/dx(3x-2)+(3x-2)d/dx(2x-1)]
RaptorsFan said:
[
= 5(2x-1)(3x-2) + 3(5x+1)(2x+1) + 2(3x-2)

Can someone validate this answer for me?

final answer looks good to me though, could always check by expanding it out

now that you know it you can make the jump

say
y = fgh

then
y' = f'(gh) + f(gh)' = f'gh + fg'h + fgh'
 
Last edited:
  • #3
Thank you for the quick response.. much appreciated.
 

FAQ: Differentiation, Product Rule 3-terms

What is differentiation?

Differentiation is a mathematical process used to find the rate of change of a function. It involves finding the derivative of a function, which represents the instantaneous rate of change at a specific point on the function.

What is the product rule for 3 terms?

The product rule for 3 terms is a formula used to find the derivative of a product of three functions. It states that the derivative of a product of three functions is equal to the first function times the derivative of the second and third functions, plus the second function times the derivative of the first and third functions, plus the third function times the derivative of the first and second functions.

When should I use the product rule for 3 terms?

The product rule for 3 terms should be used when finding the derivative of a product of three functions. It is particularly useful when the three functions cannot be simplified or combined into a single function.

How do I use the product rule for 3 terms?

To use the product rule for 3 terms, follow these steps:

  1. Identify the three functions in the product.
  2. Use the product rule formula to find the derivative, keeping in mind the order of the functions.
  3. Simplify the resulting expression if possible.

If the three functions cannot be simplified, leave the answer in its expanded form.

Can the product rule for 3 terms be extended to more than 3 terms?

Yes, the product rule for 3 terms can be extended to products of any number of terms. The formula will have additional terms for each additional function in the product. However, it is often more efficient to use other methods, such as the chain rule, when dealing with products of more than 3 terms.

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