- #1
ardentmed
- 158
- 0
Hey guys,
I have a couple of questions about this problem set I've been working on. I'm doubting some of my answers and I'd appreciate some help.
Question:
For 1a, I just separated the function into single terms with √x as the denominator. This ultimately resulted in: (5/2)x^(3/2) - (9/2)√x + 5/(2x^[3/2])
For 1b, I multiplied the outer variable into the expression in the bracket. This gave me: (4/3) w^(1/3) + (2/(3w^[5/3])) + 2e^w * (w^1/3 + 1/(3w^(2/3))
Does that look right to you guys?
As for 2a, I used the product rule and got 4x^3 *e^(-1/(x^2)) +3xe^(-1/(x^2)) - 2/x^2 * ln (2/x) + 2/(x^2)
Finally, for 2b, I just took the derivative as per usual and obtained:
(-3sin3Ø/cos3Ø) - (sin(ln(3Ø))/Ø)Thanks in advance.
I have a couple of questions about this problem set I've been working on. I'm doubting some of my answers and I'd appreciate some help.
Question:
![08b1167bae0c33982682_12.jpg](http://www.use.com/images/s_2/08b1167bae0c33982682_12.jpg?is=true&ps=true&rand=115531114628)
For 1a, I just separated the function into single terms with √x as the denominator. This ultimately resulted in: (5/2)x^(3/2) - (9/2)√x + 5/(2x^[3/2])
For 1b, I multiplied the outer variable into the expression in the bracket. This gave me: (4/3) w^(1/3) + (2/(3w^[5/3])) + 2e^w * (w^1/3 + 1/(3w^(2/3))
Does that look right to you guys?
As for 2a, I used the product rule and got 4x^3 *e^(-1/(x^2)) +3xe^(-1/(x^2)) - 2/x^2 * ln (2/x) + 2/(x^2)
Finally, for 2b, I just took the derivative as per usual and obtained:
(-3sin3Ø/cos3Ø) - (sin(ln(3Ø))/Ø)Thanks in advance.