- #1
Thepiman
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Homework Statement
A circuit consists of 230V supply, a switch, a 2mH inductor and a 12k ohm resistor in series
When the switch is closed at time t=o, a current i begins to flow in the circuit: The current is modeled by the following equation:
i= v/r (1-e^-Rt/L)
Determine the rate of change of the current at the following times:
i) t= o ns
ii) t= 1 ns
iii) t= 50 ns
I have subbed the values in and come up with answers of
i) i= 0 amps
ii) i= 1.146x10^-4 amps
iii) i= 4.968x10^-3 amps
But is this right? Do i need to insert the values in first and simplify the equation? Then differentiate it then sub in values for t?
Any help would be appreciated.
Homework Equations
i= v/r (1-e^-Rt/L)
The Attempt at a Solution
i= v/r (1-e^-Rt/L)
i= 230/12x10^3 (1-e^-12x10^3x50x10^-9/2x10^-3)
i= 0.0916 (0.25918)
i= 4.968x10^-3 amps