Differntiable at point problem

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In summary, the conversation is about proving that the function f(x) = x/(3x + 1) is differentiable at point 2. The person had attempted to use the difference quotient formula to prove it, but realized they had used the wrong formula. They then tried using the normal rules for differentiation, but were still confused. After taking a break and having a cup of tea, they were able to understand and thank the other participants for their help.
  • #1
james.farrow
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f(x) = x/(3x + 1), prove f(x) is differentiable at point 2.

Ok so I've had several attempts at this...

Using Q(h) = (f(h) - f(2))/h

I eventually end up with (h^2 -2h)/(7(3h + 1))

Obviously the above is rubbish because it I differentiate f(x) using the normal rules then

dy/dx = 1/(3x + 1)^2

What am I missing here?

Also I've tried using the difference quotient to prove it is differentiable but same result - just rubbish.

f(c + h) - f(c)/ h

The above also doesn't work out either! Please hep!
 
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  • #2
So you have the function [itex]f(x)=\frac{x}{3x+1}[/itex] and you know that a function is differentiable at [itex]a[/itex] if its derivative exists at [itex]a[/itex]. You also know that

[tex]\left.\frac{df}{dx}\right|_{a}\equiv \lim_{h\rightarrow 0}\frac{f(a+h)-f(a)}{h}=\frac{\frac{a+h}{3(a+h)+1}-\frac{a}{3a+1}}{h}[/tex]

If you simplify this does it match what you expected by using the rules you know? When you take the limit does that prove the limit exists for [itex]a=2[/itex]?
 
  • #3
james.farrow said:
f(x) = x/(3x + 1), prove f(x) is differentiable at point 2.

Ok so I've had several attempts at this...

Using Q(h) = (f(h) - f(2))/h
It would be better to use Q(h)= (f(2+ h)- f(2))/h!

I eventually end up with (h^2 -2h)/(7(3h + 1))
Obviously the above is rubbish
Yes, because you used the wrong formula for the difference quotient.

because it I differentiate f(x) using the normal rules then

dy/dx = 1/(3x + 1)^2

What am I missing here?

Also I've tried using the difference quotient to prove it is differentiable but same result - just rubbish.

f(c + h) - f(c)/ h

The above also doesn't work out either! Please hep!
 
  • #4
Jefferydk if I simplify it I end up with nothing like? Whats going on...?
 
  • #5
Err after a cup of tea and a break the penny drops...

Thanks for your help lads! No doubt I'll call on you again!

James
 
  • #6
A cup of tea works wonders!

(I used to do my best work after a couple glasses of rum- but then I could never find the papers where I had written it all down!)
 

FAQ: Differntiable at point problem

What is a differentiable at point problem?

A differentiable at point problem involves determining whether a function is differentiable at a specific point on its domain. This means that the function has a well-defined derivative at that point, which represents the rate of change of the function at that point.

How do you determine differentiability at a point?

To determine differentiability at a point, we can use the definition of the derivative to calculate the limit of the function as the input approaches the point in question. If this limit exists, then the function is differentiable at that point.

What are the necessary conditions for differentiability at a point?

There are two necessary conditions for differentiability at a point: the function must be continuous at that point, and the limit of the function as the input approaches the point must exist. If either of these conditions is not met, then the function is not differentiable at that point.

Can a function be differentiable at just one point?

Yes, a function can be differentiable at just one point. This means that it is not differentiable at any other point on its domain, but it does have a well-defined derivative at that specific point.

How is differentiability at a point related to continuity?

Differentiability at a point is related to continuity because a function must be continuous at that point in order for it to be differentiable at that point. However, a function can be continuous at a point without being differentiable at that point.

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