- #1
james.farrow
- 44
- 0
f(x) = x/(3x + 1), prove f(x) is differentiable at point 2.
Ok so I've had several attempts at this...
Using Q(h) = (f(h) - f(2))/h
I eventually end up with (h^2 -2h)/(7(3h + 1))
Obviously the above is rubbish because it I differentiate f(x) using the normal rules then
dy/dx = 1/(3x + 1)^2
What am I missing here?
Also I've tried using the difference quotient to prove it is differentiable but same result - just rubbish.
f(c + h) - f(c)/ h
The above also doesn't work out either! Please hep!
Ok so I've had several attempts at this...
Using Q(h) = (f(h) - f(2))/h
I eventually end up with (h^2 -2h)/(7(3h + 1))
Obviously the above is rubbish because it I differentiate f(x) using the normal rules then
dy/dx = 1/(3x + 1)^2
What am I missing here?
Also I've tried using the difference quotient to prove it is differentiable but same result - just rubbish.
f(c + h) - f(c)/ h
The above also doesn't work out either! Please hep!