- #1
throneoo
- 126
- 2
Homework Statement
How to evaluate the anti-derivative of [x+(7x^2)]^(1/3) ?
2. The attempt at a solution
I've attempted to do so via standard integration techniques , i.e. substitution and integration by parts , but the problem simply becomes increasingly complicated . I've even tried to manipulate it into a perfect square in hopes of getting an easier expression but that failed too.
My substitution : u=(x+7x^2) ; du=(1+14x)dx and x=(+/-(1+28u)^(0.5)-1)/14
making the intergrand u^(1/3)(1+28u)^-0.5
with by parts things get so complicated it terrified me.
Frustrated , I tried wolfram alpha ,only to get sth like this :
http://www4c.wolframalpha.com/Calculate/MSP/MSP4182022fe0gi4018be9000021e9375hf3bi1a91?MSPStoreType=image/gif&s=36&w=569.&h=56.
I don't even know what a hypergeometric function is
Can anyone help me ?
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