- #1
jmher0403
- 22
- 0
Homework Statement
A digital filter is defined by yn = xn - n-2 - 0.81*yn-2.
At what frequency, in terms of fNyquist, is the filter response zero and maximum?
Homework Equations
H(z) = Y(z)/X(z)
The Attempt at a Solution
I figured out that H(z) = [z2-1] /[z2 +0.81]
and F(w) = [e2jwt -1 ] / [e2jwt + 0.81]
= [cos(2wt) + isin(2wt) - 1] / [cos(2wt) + isin(2wt) + 0.81]
Please give me some advice on how to go on about finding the frequencies please...
Hint was given that wt = ∏ f/fNyquist
please also explain why this is so...
Thanks a lot in advance :D