- #1
CoolDude420
- 201
- 9
Homework Statement
Homework Equations
The Attempt at a Solution
The correct answer is 0.25V. I'm getting 0.3335V[/B]
gneill said:Check your Thevenin voltage derivation.
gneill said:Still incorrect. You're mucking up after the first stage when you apply the voltage division with the 500 Ohm resistor. Take the circuit one stage at a time:
View attachment 114680
First break the circuit at (1) and find the Thevenin equivalent. What do you find?
gneill said:No. There are three resistors involved and you haven't dealt with the voltage divider. A Thevenin model consists of a voltage source with a series resistance and does not form a closed loop!
gneill said:No. How do you arrive at 2 kΩ? How come the original 2 V hasn't been divided by the voltage divider consisting of the two 1 kΩ resistors? This is the circuit that you are starting with for this first part:
View attachment 114681
Apply the procedure to find its Thevenin equivalent.
gneill said:Right!
Now tack on the next stage and repeat:
View attachment 114682
What's the Thevenin equivalent for the terminals at (2)?
Great.CoolDude420 said:Ah. I seem to have gotten it now. Thank you, not entirely sure why my method that I did initially to find Vth is wrong.
gneill said:Great.
You were doing something strange with 1.5 kΩ that I couldn't see the reasoning behind. It's best to either break the circuit up into discrete stages and proceed methodically, or apply something like mesh or nodal analysis when you want to do it all at once.
The problem is that you started finding the Thevenin equivalent for the first section of the circuit and did not complete the operation before you applied the partial result to the next section. Your paragraph labelled (2) assumed that the 1 V first Thevenin voltage would be expressed across the first vertical 1 k resistor and hence would be applied to the following section's voltage divider consisting of the 500 Ω resistor and 1k Ω resistor. That was an error. The 1 V should be behind a 1 kΩ series resistor (the Thevenin resistance of the first stage) that includes the 500 Ω resistor.CoolDude420 said:Okay, I've written in detail to what my approach was. I have a feeling that I'm neglecting that extension of A-B at the right and assuming no current flows? But isn't that what I'm meant to do. I mean Vth is the open circuit voltage?
Thanks!gneill said:The problem is that you started finding the Thevenin equivalent for the first section of the circuit and did not complete the operation before you applied the partial result to the next section. Your paragraph labelled (2) assumed that the 1 V first Thevenin voltage would be expressed across the first vertical 1 k resistor and hence would be applied to the following section's voltage divider consisting of the 500 Ω resistor and 1k Ω resistor. That was an error. The 1 V should be behind a 1 kΩ series resistor (the Thevenin resistance of the first stage) that includes the 500 Ω resistor.
A diode is a two-terminal electronic component that allows electric current to flow in only one direction. It acts as a one-way valve for electricity, allowing current to flow from the anode (positive terminal) to the cathode (negative terminal) but not in the reverse direction.
A diode is made of a semiconductor material, usually silicon, with impurities added to create a p-type and n-type region. When a voltage is applied across the diode in the forward direction, the p-n junction allows current to flow. However, in the reverse direction, the p-n junction acts as an insulator and prevents current flow.
Thevenin's Theorem is a theorem in circuit analysis that states any linear network with voltage and current sources can be replaced by an equivalent circuit consisting of a single voltage source in series with a single resistor. This is helpful in simplifying complex circuits and determining the behavior of a circuit at a specific point.
In diode analysis, Thevenin's Theorem can be used to simplify a circuit and determine the voltage and current at a specific point. The diode can be replaced by its equivalent circuit consisting of a voltage source (Vd) and a resistor (Rd). This allows for easier calculation of the diode's behavior without having to consider the rest of the circuit.
Thevenin's Theorem assumes that the circuit is linear, meaning that the voltage-current relationship is constant. However, diodes have a nonlinear voltage-current relationship, so the theorem may not be accurate in all cases. Additionally, Thevenin's Theorem does not take into account the effects of temperature and aging on the diode, which can also affect its behavior.