- #1
Woolyabyss
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Homework Statement
A ball of mass m moves horizontally with speed 20 m/s towards a smooth barrier xy which makes an angle tan-inverse(4/3) with the horizontal.The coefficient of restitution is (3/4)
find
(i) The speed of the ball after the impact
(ii) The magnitude of the impulse due to the impact
(iii) the loss in kinetic energy
(iv) the tan of the angle between the ball's new path and the horizontal
Homework Equations
The Attempt at a Solution
let barrier xy = x axis
i = horizontal component vector
j = vertical component vector
(i)
resolving 20 m/s into component vectors 20(3/5) = 12i 20(4/5) = -16j
12i - 16j
i component remains the same
16(3/4) 12j
12i +12 j (changes direction) using Pythagoras theorem to find magnitude = 12√2 m/s
(ii)
since only the j vector changes
12m -(-16m ) = 28m Ns
(iii) (1/2)m(20^2) - (1/2)m(12√2)^2 = 56m j
(iv)
(12i - 16j) + (12i + 12j) = 24i - 4j j/i = tan∅ = 4/24 = 1/6
I got the right answers for part (i), (ii) and (iii)
(iv) is the part I am stuck on, is it not as simple as adding the two vectors and finding the angle? the answer at the back of my book is 7