- #1
vrobins1
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Homework Statement
An electron moves with speed 4.00 105 m/s in a uniform magnetic field of 3.2 T, pointing south. At one instant, the electron experiences an upward magnetic force of 1.00 10-14 N. In what possible directions might the electron be moving at that instant? Give your answers as angles clockwise from south (from 0° to 360°), in increasing degrees.
(I have to find two answers in degrees, both clockwise from south).
Homework Equations
F = qvBsin(theta)
The Attempt at a Solution
F = qvBsin(theta)
sin(theta) = F / qvB
= (1x10-14) / [(1.6x10-19)(4x105)(3.2)]
= .0488
theta = sin-1(.0488)
theta = 2.8
So my first angle was approximately 2.8. I subtracted that from 270 degrees ("south") to get my final angle of 267.2 degrees. Then I subtracted 2.8 from 180 to get my second angle, which was approximately 177.2. I subtracted THAT number from 270 degrees to get my final second angle of approximately 92.8 degrees. I thought that 267.2 and 92.8 were my answers, but they are coming up as incorrect. I also tried rounding to a whole number, which didn't work either.