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EV33
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Homework Statement
I don't have an actual problem but is what I am trying to make sure I have clear is...
What direction in general is
Asin(kx+or-wt) going?
Asin(kx+wt) Left
Asin(kx-wt) Right
Asin(-kx-wt)=-Asin(kx+wt) Left
Asin(-kx+wt)=-Asin(kx-wt) Right
Acos(kx+wt) Left
Acos(kx-wt) Right
Acos(-kx+wt)?
Acos(-kx-wt)?
Homework Equations
Asin(kx-wt) is to the right
Asin(kx+wt) is to the left
Is what I have been taught to help me figure out the direction.
The Attempt at a Solution
I am pretty sure the ones I answered are correct but if they're please let me know.
My trouble is that as far as I know I can't take a negative out of the cos function like I can the sin function, so the only thing I have thought of thus far...
Acos(-kx+wt)=Asin(-kx+wt+pi/2)=-Asin(kx-wt-pi/2)
So I would say this goes to the right because it is minus wt.
Does that work?