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In summary, the polynomial shown in the picture has roots with negative real parts for values of k greater than -2, according to the Routh array criteria.
  • #1
engnrshyckh
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2
Homework Statement
For what value of k does the polynomial shown in picture have roots with negative real parts
Relevant Equations
Rooth array criteria
See the picture
I am stuck at 12(1+2k)=0
So k=-1/2 for stability k must have value greater the - 1/2 which means there will no sign changes in rooth array and equation represents a stable system
 

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  • #2
engnrshyckh said:
Homework Statement:: For what value of k does the polynomial shown in picture have roots with negative real parts
Relevant Equations:: Rooth array criteria

See the picture
I am stuck at 12(1+2k)=0
So k=-1/2 for stability k must have value greater the - 1/2 which means there will no sign changes in rooth array and equation represents a stable system
But correct ans is k>-2
 
  • #3
engnrshyckh said:
Homework Statement:: For what value of k does the polynomial shown in picture have roots with negative real parts
Relevant Equations:: Rooth array criteria

See the picture
I am stuck at 12(1+2k)=0
So k=-1/2 for stability k must have value greater the - 1/2 which means there will no sign changes in rooth array and equation represents a stable system
First off, the name is Routh. I've never heard of this algorithm, but I found something about Routh-Hurwitz stability at this wiki page - https://en.wikipedia.org/wiki/Routh–Hurwitz_stability_criterion

In the section titled Routh–Hurwitz criterion for second and third order polynomials, it says,
The third-order polynomial
##P ( s ) = s^3 + a_2 s^2 + a_1 s + a_0## has all roots in the open left half plane if and only if
##a_2 , a_0## are positive and ##a_2 a_1 > a_0## .
In your problem, ##a_2 = 4 + 4k, a_1 = 6, a_0 = 12##
The solution to both inequalities is k > -1, so it seems to me that the closest of the given answers is k > -2.
 

FAQ: Discover the Stability of the System through a Visualization | Learn More

What is the purpose of visualizing system stability?

The purpose of visualizing system stability is to gain a better understanding of how a system functions and to identify any potential issues or weaknesses within the system. By visualizing data and processes, scientists can more easily identify patterns and trends that may affect the stability of the system.

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