Discovering When cos(x) - sin(x) < cos(x) + sin(x)

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The discussion focuses on determining the values of x for which the inequality cos(x) - sin(x) < cos(x) + sin(x) holds within the interval 0 ≤ x ≤ 2π. The conclusion reached is that the inequality is satisfied for the interval (0, π), as derived from algebraic manipulation showing that 0 < sin(x). Initial confusion arose from discrepancies between graphical results and algebraic findings, but ultimately, the mathematical reasoning was confirmed to align with the graphs. The participant acknowledged a mistake in their initial graph interpretation, leading to a resolution of the problem. The discussion highlights the importance of verifying graphical results against algebraic solutions.
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Homework Statement



for what values of x is cos(x) - sin(x) < cox(x) + sin(x) where 0 =< x =< 2pi

Homework Equations



none.

The Attempt at a Solution



I actually drew out the funtions and added them.
In my graphs, I get that:

cos(x) - sin(x) < cos(x) + sin(x) for for 0 =< x =< pi

When I try to show this in Matlab, i ger messy results?

Any ideas?
 
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There's a simpler way to do it. Did you try algebraically manipulating the equation?
 
no ... infact, I am not sure what you mean?

cos(x) - sin(x) < cos(x) + sin(x)
cos(x) - cos(x) < sin(x) + sin(x)
0 < 2sin(x)
0 < sin(x)

and sin(x) is bigger than zero for 0 =< x =<pi/2

This dosn't seem right to me...
 
Actually, sin(x)>0 everywhere on the open interval (0,pi).
 
oh yeah, sorry, i got confused...

so that means that cos(x) - sin(x) is less than cos(x) + sin(x) for (0,pi) ?
 
Yes. 10char[/color]
 
i don't like this because it dosn't match up with my graphs.

but the math looks right, therefore, their must exist an error in my graphs.
 
opps, it actually does match with my graphs... :)
 

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