Displacement Using Tabular Reimann Sum

In summary, the problem involves finding the displacement using a midpoint Reimann sum with 4 subintervals of equal width. The given data includes the time intervals and corresponding velocity values. The correct value of delta x is 24.
  • #1
Qube
Gold Member
468
1

Homework Statement



Find the displacement using a midpoint Reimann sum with 4 subintervals of equal width.

minute 0, 12, 24, 36, 48, 60, 72, 84, 96
ft/min -4, -4, 1, 4, 5, -6, 0, 5, 2

Homework Equations



Displacement is the final position minus starting position.

The Attempt at a Solution



Reimann sum:

delta x = 12

12[-4 + 4 + -6 + 5] I'm choosing all the ft/min values at the midpoints (which are 12, 36, 60, and 84).

12[-1] = -12 feet.

This isn't the correct answer however.
 
Physics news on Phys.org
  • #2
Qube said:

Homework Statement



Find the displacement using a midpoint Reimann sum with 4 subintervals of equal width.

minute 0, 12, 24, 36, 48, 60, 72, 84, 96
ft/min -4, -4, 1, 4, 5, -6, 0, 5, 2

Homework Equations



Displacement is the final position minus starting position.

The Attempt at a Solution



Reimann sum:

delta x = 12

12[-4 + 4 + -6 + 5] I'm choosing all the ft/min values at the midpoints (which are 12, 36, 60, and 84).

12[-1] = -12 feet.

This isn't the correct answer however.

Now why do you think Δx=12?
 
  • Like
Likes 1 person
  • #3
Oops. I was thinking of a Reimann sum with 8 subintervals I suppose. Delta x is 24. That would make a lot more sense.
 

FAQ: Displacement Using Tabular Reimann Sum

What is "Displacement Using Tabular Reimann Sum"?

"Displacement Using Tabular Reimann Sum" is a mathematical method used to approximate the change in position of an object over time. It involves dividing the time interval into smaller intervals and calculating the area under the velocity-time graph for each interval.

Why is "Displacement Using Tabular Reimann Sum" important?

"Displacement Using Tabular Reimann Sum" allows scientists to estimate the displacement of an object when the exact function of its motion is not known. This method is particularly useful in physics and engineering when analyzing the motion of objects.

What is the difference between "Displacement Using Tabular Reimann Sum" and other methods of calculating displacement?

The main difference is that "Displacement Using Tabular Reimann Sum" uses a series of rectangles to approximate the area under the velocity-time graph, while other methods such as the trapezoidal rule use a combination of rectangles and trapezoids. Additionally, "Displacement Using Tabular Reimann Sum" is typically used for non-linear functions, while other methods may be used for both linear and non-linear functions.

What are the limitations of "Displacement Using Tabular Reimann Sum"?

One limitation is that the method can only provide an approximation of the actual displacement and may not be completely accurate. The accuracy of the approximation also depends on the number of subintervals used. Additionally, this method is not suitable for functions with constantly changing acceleration.

How is "Displacement Using Tabular Reimann Sum" calculated?

To calculate the displacement using this method, the time interval is divided into subintervals of equal length. The velocity at the beginning of each subinterval is multiplied by the length of the subinterval to determine the area of the rectangle. The sum of these areas for all the subintervals gives an approximation of the total displacement.

Similar threads

Back
Top