Distance Across I Don't Know Where to Begin

  • MHB
  • Thread starter Ilikebugs
  • Start date
In summary, the conversation discusses using variables to represent the lengths of segments with tick marks and the Pythagorean theorem to find the dimensions of a white rectangle on a tile. The length of the diagonal of the rectangle is found to be 10 cm using the given information.
  • #1
Ilikebugs
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View attachment 6484 I don't know where to begin
 

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  • #2
I would let $a$ be the length (in cm) of the segments with 1 tick mark, and $b$ be the length (in cm) of the segments with 2 tick marks. And so, given the statement regarding the area of the colored sections, we may write:

\(\displaystyle a^2+b^2=50\)

In terms of $a$ and $b$, what are the dimensions of the white rectangle within the tile?
 
  • #3
√2a^2 and √2b^2
 
  • #4
Ilikebugs said:
√2a^2 and √2b^2

Not quite...it would be \(\displaystyle \sqrt{2}a\) and \(\displaystyle \sqrt{2}b\)...so what would the diagonal of the rectangle be?
 
  • #5
sqr(2a+2b) ?
 
  • #6
Ilikebugs said:
sqr(2a+2b) ?

Using the Pythagorean theorem, we find:

\(\displaystyle \overline{MK}=\sqrt{(\sqrt{2}a)^2+(\sqrt{2}b)^2}=\sqrt{2\left(a^2+b^2\right)}\)

Now, we know that $a^2+b^2=50$, so what is the length of $\overline{MK}$?
 
  • #7
|MK|=√(a√2)^2+(b√2)^2?
 
  • #8
Ilikebugs said:
|MK|=√(a√2)^2+(b√2)^2?
MK equals 100?
 
  • #9
Ilikebugs said:
MK equals 100?

\(\displaystyle \overline{MK}=\sqrt{(\sqrt{2}a)^2+(\sqrt{2}b)^2}=\sqrt{2\left(a^2+b^2\right)}=\sqrt{2(50)}=\sqrt{100}=10\) :D
 

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