- #1
skrat
- 748
- 8
Homework Statement
I had to calculate the probability that we find electron more than 0.1 nm away from proton in Hydrogen atoms if ##\psi _{n,l,m}=\psi _{1,0,0}## (i don't know the english word for this state, but I think we all know what we are talking about :D)
My result is 0.09957.
Now I am questioning myself if that makes any sense at all... Correct me if I am wrong: Bohr radius is expected value for distance between electron and proton in Hydrogen atoms for ##\psi _{1,0,0}##.
If that is true, and if ##r_B=5.29*10^{-11}m## than my result makes some sense...
Homework Equations
The Attempt at a Solution
##\psi _{1,0,0}=R_{1,0}(r)Y_{0,0}(\theta ,\varphi )## where ##R_{1,0}=\frac{1}{\sqrt{4\pi }}\frac{2}{r^{3/2}}e^{-\frac{r}{r_B}}##
than ##P(r>0.1 nm)=\int_{0.1 nm}^{\infty }\frac{1}{4\pi }\frac{4}{r^{3}}e^{-\frac{2r}{r_B}}4\pi r^2dr##
##P(r>0.1 nm)=\frac{1}{2}\int_{\frac{0.2 nm}{r_B}}^{\infty }u^2e^{-u} dr##
##P(r>0.1 nm)=\frac{1}{2}e^{\frac{0.2nm}{r_B}}(4(\frac{0.1 nm}{r_B})^{2}-4(\frac{0.1 nm}{r_B})+2)##
which should be 0.09957...
Does this sound ok?