MHB Distance between points in a triangle

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In an equilateral triangle with a side length of 2, placing five points inside ensures that at least two points are within 1 unit of each other, as demonstrated by the pigeonhole principle. By dividing the triangle into four smaller equilateral triangles, at least one of these smaller triangles must contain at least two points. The maximum distance between any two points within one of these smaller triangles is 1 unit, as shown by geometric reasoning involving arcs. Concerns about points lying on the edges of the smaller triangles do not disprove the theory, as the maximum distance still holds true. The discussion highlights the application of geometric principles and the pigeonhole principle in proving point proximity within a triangle.
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Hello all,

Below there is a problem:

There are five points inside an equilateral triangle of side length 2. Show that at least two of the points are within 1 unit distance from each other.

I have plotted such a triangle using "Geogebra", and attaching the picture.

I know that if I create another equilateral triangle within the original one, I get four triangles. Then, according to the pigeonhole principle, with 5 points (pigeons) and 4 triangle (holes), at least two points will be in the same triangle.

My questions are:

1) What is the geometrical reasoning for claiming that two points within a triangle will have a distance of 1 units max ? I couldn't prove it.
2) What happens if a point in the bigger triangle happens to be on the edge of the inner black triangle? Doesn't it disproof the theory ?

Thank you in advance !

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Yankel said:
Hello all,

Below there is a problem:

There are five points inside an equilateral triangle of side length 2. Show that at least two of the points are within 1 unit distance from each other.

I have plotted such a triangle using "Geogebra", and attaching the picture.

I know that if I create another equilateral triangle within the original one, I get four triangles. Then, according to the pigeonhole principle, with 5 points (pigeons) and 4 triangle (holes), at least two points will be in the same triangle.

My questions are:

1) What is the geometrical reasoning for claiming that two points within a triangle will have a distance of 1 units max ? I couldn't prove it.
2) What happens if a point in the bigger triangle happens to be on the edge of the inner black triangle? Doesn't it disproof the theory ?

Thank you in advance !

Suppose there are 2 points in the triange CDE.

the largest distance between any 2 points in CDE (The points in the edges included) is 1.

to prove the same draw an arc with centre C and distance 1
DE line segment shall be in the arc and any poins in DE shall be < 1 (unless end point D or E for which distance = 1)
so maximum distance is 1
 
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