Distance between two bright fringes

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In summary, the distance between the second order bright fringe of light with wavelength 683 nm and the third order bright fringe of light with wavelength 400 nm is calculated using the equation sin∅=mλ/d, where ∅ is the angle, m is the order, λ is the wavelength, and d is the spacing between slits. The values of ∅ and D, the distance between the central bright fringe and the desired bright fringe, are calculated for each wavelength and the difference D_683-D_400 is taken to find the distance between the two fringes. However, it is suggested to also consider the width of each fringe to find the smallest possible distance.
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csinger1
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Homework Statement


A new experiment is created with the screen at a distance of 2.2 m from the slits (with spacing 0.12 mm). What is the distance between the second order bright fringe of light with l = 683 nm and the third order bright fringe of light with l = 400 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.)



Homework Equations


sin∅=mλ/d


The Attempt at a Solution


For first wavelength,
∅=arcsin(2(683*10^-9)/1.2*10^-4)
∅=.65
Setting up triangle, I get D_683=2.2tan(.65)=.0249

For second wavelength,
∅=arcsin(3(400*10^-9)/1.2*10^-4)
∅=.57
Setting up triangle, I get D_400=2.2tan(.57)=.0219
I thought that D_683-D_400 should give me the distance between the two fringes but my answer of .003m keeps getting rejected. I have done this problem over and over and I cannot for the life of me figure out what I am doing wrong.
 
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  • #2
The math looks pretty solid to me. Not quite sure why that answer would be rejected. Sorry if that's not helpful.
 
  • #3
csinger1 said:

Homework Statement


A new experiment is created with the screen at a distance of 2.2 m from the slits (with spacing 0.12 mm). What is the distance between the second order bright fringe of light with l = 683 nm and the third order bright fringe of light with l = 400 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.)



Homework Equations


sin∅=mλ/d


The Attempt at a Solution


For first wavelength,
∅=arcsin(2(683*10^-9)/1.2*10^-4)
∅=.65
Setting up triangle, I get D_683=2.2tan(.65)=.0249

For second wavelength,
∅=arcsin(3(400*10^-9)/1.2*10^-4)
∅=.57
Setting up triangle, I get D_400=2.2tan(.57)=.0219
I thought that D_683-D_400 should give me the distance between the two fringes but my answer of .003m keeps getting rejected. I have done this problem over and over and I cannot for the life of me figure out what I am doing wrong.

Might want to find the width of each fringe too, it does state smallest possible value, but with your calculation it is not smallest possible value.
 

FAQ: Distance between two bright fringes

What is the distance between two bright fringes?

The distance between two bright fringes refers to the distance between the center of one bright fringe to the center of the next bright fringe in an interference pattern. It is a measure of the wavelength of the light source used.

How is the distance between two bright fringes calculated?

The distance between two bright fringes can be calculated using the equation d = λL/D, where d is the distance between fringes, λ is the wavelength of the light, L is the distance between the light source and the screen, and D is the distance between slits or diffraction grating.

What factors affect the distance between two bright fringes?

The distance between two bright fringes is affected by the wavelength of the light, the distance between the light source and the screen, and the distance between the slits or diffraction grating. Any changes in these factors can alter the distance between the fringes.

How does the distance between two bright fringes relate to the intensity of light?

The distance between two bright fringes does not directly relate to the intensity of light. Instead, it is determined by the wavelength of light and the distance between the light source and the screen. However, the intensity of light does affect the brightness of the fringes.

Can the distance between two bright fringes be changed?

Yes, the distance between two bright fringes can be changed by altering the wavelength of the light, the distance between the light source and the screen, or the distance between the slits or diffraction grating. Additionally, changing the angle of the light can also affect the distance between the fringes.

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