- #1
Physgeek64
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Homework Statement
An alpha particle is accelerated from rest through a potential difference of 20kV. It travels directly towards
a stationary Beryllium nucleus (4 protons, 5 neutrons). Calculate the distance of closest approach
Homework Equations
The Attempt at a Solution
E=qv=(40x10^3)e, where e is the electronic charge
U=qQ/4(pi)(epsilon naught)(R)
R=qQ/4(pi)(epsilon naught)(U)
R=2.876x10-13 m
Is there any more to this question- it seems a bit to simple for it to be just this. Wondering if I've missed something blindingly obvious. Thanks :)