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dani123
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Homework Statement
Jaime is outside playing with her dog, Skip. She throws a tennis ball at an angle of 60° with an initial speed of 10.2m/s and from a height of 196cm. If Skip was standing beside her when she threw the ball, how far would Skip have to run in order to catch the ball just the moment before it hits the ground?
Homework Equations
dv=1/2*at2
dh=Vh*Δt
Kinetic equation d=Vi*t+ 1/2*at2
dh=-V2*sin2θ /g
sinθ=opp/hyp
cosθ=adj/hyp
Δt=-2Vsinθ / g
The Attempt at a Solution
dv= sin(60)*10.2m/s= 8.83m
The actual vertical height for the dog is 1.96m+8.83m=10.8m
t=√[10.8m/(0.5)*(9.8)]=1.48s
Then dv=1/2*at2= 25.9m
If someone could just verify my work and make sure my answers are correct that would be greatly appreciated. Also, if you could check my significant figures are being respected. Thanks so much in advance!