- #1
lha08
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Homework Statement
The focal length of a diverging lens is -20 cm. Locate the object, given that the image is real, erect, and 150% of the size of the object.
Homework Equations
(1/f)=(1/do)+(1/di)
M=-(di/do)
The Attempt at a Solution
i'm not really sure how a diverging lens forms a real image (i thought they could only from virtual since most of the images are on the same side) and a size that is larger than the original object. At first, I thought that the image would be inverted (negative magnification) since a virtual image would have a positive magnification (image is upright)...