- #1
PsychonautQQ
- 784
- 10
I will be using /= to mean 'does not equal'.
From my textbook:
Division Algorithm: Let R be any ring and let f(x) and g(x) be polynomials in R[x]. Assume that f(x) /= 0 and that the leading coefficient of f(x) is a unit in R. then unique determined polynomials q(x) and r(x) exist such that
1) g(x) = q(x)f(x) + r(x)
2) Either r(x) = 0 or deg[r(x)] < deg[f(x)]
Can somebody explain to me why the following values for the given functions is invalid?
q(x) = 2x+3
f(x) = 3x+4
r(x) = 3x^2
g(x) = 9x^2 +17x+12
These polynomials work and deg[r(x)] = deg[f(x)], more importantly, deg[r(x)] is not less than deg[f(x)].
I'm assuming part of the reason why what I said is invalid is because f(x) and g(x) aren't polynomails in R[x] or something? Need some math guru to help this noob :D
From my textbook:
Division Algorithm: Let R be any ring and let f(x) and g(x) be polynomials in R[x]. Assume that f(x) /= 0 and that the leading coefficient of f(x) is a unit in R. then unique determined polynomials q(x) and r(x) exist such that
1) g(x) = q(x)f(x) + r(x)
2) Either r(x) = 0 or deg[r(x)] < deg[f(x)]
Can somebody explain to me why the following values for the given functions is invalid?
q(x) = 2x+3
f(x) = 3x+4
r(x) = 3x^2
g(x) = 9x^2 +17x+12
These polynomials work and deg[r(x)] = deg[f(x)], more importantly, deg[r(x)] is not less than deg[f(x)].
I'm assuming part of the reason why what I said is invalid is because f(x) and g(x) aren't polynomails in R[x] or something? Need some math guru to help this noob :D