- #1
Living_Dog
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After deriving the Lagrangian for the electromagnetic field using only gauge invariance of the action, the result is: (i.e. to say [tex]\delta L \equiv 0[/tex].)
[tex]L \equiv (\partial_{\mu} + ieA_{\mu})\phi(\partial^{\mu} - ieA^{\mu})\phi^* - m^2\phi^2[/tex].
Et. viola'. Done. Finished. Complete. Let's go home and party till it's 1999.
WRONG CAMEL BREATH!
Ryder then pulls out a statement from some orifice unbeknown to ex-graduate wanna-be physicist students, to wit:
"The field [tex]A_{\mu}[/tex], however, must presumably contribute by itself to the Lagrangian."
When I read that I heard a very loud "pop" as if the entrance to said orifice was suddenly opened and closed. So a big hug to the person who defends... I mean explains this in Ryder!:)
Ok, all joking aside, I know we need the electromagnetic field strength tensor in order to recover E&M from the Lagrangian when we vary [tex]A_{\mu}[/tex]. But the above statement is so ad hoc and short that if this was some unknown field no one would know to add any other term whatsoever. ... no?
-ld
[tex]L \equiv (\partial_{\mu} + ieA_{\mu})\phi(\partial^{\mu} - ieA^{\mu})\phi^* - m^2\phi^2[/tex].
Et. viola'. Done. Finished. Complete. Let's go home and party till it's 1999.
WRONG CAMEL BREATH!
Ryder then pulls out a statement from some orifice unbeknown to ex-graduate wanna-be physicist students, to wit:
"The field [tex]A_{\mu}[/tex], however, must presumably contribute by itself to the Lagrangian."
When I read that I heard a very loud "pop" as if the entrance to said orifice was suddenly opened and closed. So a big hug to the person who defends... I mean explains this in Ryder!:)
Ok, all joking aside, I know we need the electromagnetic field strength tensor in order to recover E&M from the Lagrangian when we vary [tex]A_{\mu}[/tex]. But the above statement is so ad hoc and short that if this was some unknown field no one would know to add any other term whatsoever. ... no?
-ld
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