- #1
PainterGuy
- 940
- 70
Hi,
In the link given below circuit #1 and #2 are same except that they have opposite polarities for the battery V. On the left bottom there is output waveform after the clipping. In the beginning I was thinking that output for both circuits, #1 and #2, will be same. But now I am doubtful! The diode D1 starts conducting when its anode is more positive than cathode and there is potential difference across them of at least 0.7V. Let's assume the battery V is of 6 volts.
Link:--
http://img687.imageshack.us/img687/716/changingpolarityofbatte.jpg
Do both circuits have the same output which is given on left bottom? Tell me please. Much grateful for any help you can give me.
Cheers
In the link given below circuit #1 and #2 are same except that they have opposite polarities for the battery V. On the left bottom there is output waveform after the clipping. In the beginning I was thinking that output for both circuits, #1 and #2, will be same. But now I am doubtful! The diode D1 starts conducting when its anode is more positive than cathode and there is potential difference across them of at least 0.7V. Let's assume the battery V is of 6 volts.
Link:--
http://img687.imageshack.us/img687/716/changingpolarityofbatte.jpg
Do both circuits have the same output which is given on left bottom? Tell me please. Much grateful for any help you can give me.
Cheers
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