Do electric currents depend on the frame of reference?

In summary, electric currents do depend on the frame of reference due to the principles of special relativity. Observers in different inertial frames may measure different electric fields and consequently different currents when moving relative to a charged system. This is because the motion of charges affects the electric and magnetic fields experienced by an observer, leading to variations in the observed current. Thus, the measurement of electric currents is frame-dependent, highlighting the interplay between electricity and relativity.
  • #1
Meow12
45
20
Suppose you have an infinite straight wire carrying electric current I. If you move in the direction of the electrons (opposite to the direction of the current) at the drift speed, would the current be zero in your new reference frame? Why or why not?
 
Physics news on Phys.org
  • #2
No, it would not be zero because, while the (conduction) electrons are standing still, the rest of the wire (including all positive charges) is moving.

That doesn’t mean current is not different. Together with the charge density, current density forms a 4-vector called the 4-current density, which also transforms accordingly. For example, the wire will appear to have a net charge density in other frames even if neutral in its rest frame.
 
  • Like
Likes vanhees71, Drakkith and Meow12
  • #3
Meow12 said:
Suppose you have an infinite straight wire carrying electric current I. If you move in the direction of the electrons (opposite to the direction of the current) at the drift speed, would the current be zero in your new reference frame? Why or why not?
So this can be figured out using the four-current density. This is the relativistic quantity that enters Maxwell's equations and transforms correctly between reference frames. In an inertial frame it is defined as ##\mathbf J=(c \rho,\vec j)## where ##\rho## is the charge density and ##\vec j## is the current density.

So, in a current carrying wire the electrons are drifting with some velocity ##-\vec v##. So they have a four-current density ##\mathbf J_e=(-c \rho, \vec v \rho)## and the protons have a four-current density ##\mathbf J_p = (c \rho,0)##, so the total current density is ##\mathbf J = \mathbf J_e + \mathbf J_p = (0,\vec v \rho)##

Now, if we Lorentz transform to a frame where the electrons are at rest then we get ##\mathbf J'_e=(-\gamma c \rho + \gamma \rho v^2/c,0)##, so there is no current due to the electrons. However, we also have ##\mathbf J'_p=(\gamma c \rho, \gamma \vec v \rho)## for a total current density ##\mathbf J = (\gamma \rho v^2/c,\gamma \vec v \rho)##.

You can plot the total current as a function of reference frame. It turns out that the current density is the lowest in the reference frame where the charge density is 0. In all other frames the current density is ##\gamma v \rho## where ##\gamma## is based on the velocity of the reference frame wrt the uncharged frame rather than the drift velocity. Since ##\gamma## is always greater than 1 the current density is also always greater.
 
  • Like
Likes Meow12
  • #4
Orodruin said:
No, it would not be zero because, while the (conduction) electrons are standing still, the rest of the wire (including all positive charges) is moving.

That doesn’t mean current is not different. Together with the charge density, current density forms a 4-vector called the 4-current density, which also transforms accordingly. For example, the wire will appear to have a net charge density in other frames even if neutral in its rest frame.
The wire is neutral (i.e., has 0 charge density in its interior) in the rest frame of the electrons. It's an often made wrong statement to claim it's neutral in the rest frame of the ion lattice. For details, see the newest version of my writeup about it:

https://itp.uni-frankfurt.de/~hees/pf-faq/relativistic-dc.pdf

Right now, I'm still thinking about an approximate treatment of a coax wire of finite length with a voltage source on one end and a resistor at the other. The fully exact treatment of this seems to be not possible analytically, but an approximate treatment should be possible. We'll see...
 
  • #5
vanhees71 said:
The wire is neutral (i.e., has 0 charge density in its interior) in the rest frame of the electrons. It's an often made wrong statement to claim it's neutral in the rest frame of the ion lattice.
The wire can be any charge in any frame. The wire includes both the bulk charge (which behaves as you derived) and also the surface charge (which can be adjusted as desired). It is not a wrong statement, it is just a specification of boundary conditions.
 
  • #6
The wire as a whole is of course electrically neutral (i.e., taking into account both the inner and the outer conductor of the coax cable in my writeup; both conductors for themselves are charged). Of course you have to take into account both the bulk charge densities in the wire as well as the surface-charge densities.

See Eqs. (45-48) in

https://itp.uni-frankfurt.de/~hees/pf-faq/relativistic-dc.pdf

What I was referring to was the bulk charge density within the conductors, which is 0 in the rest frame of the electrons rather than in the rest frame of the ion lattice.
 

FAQ: Do electric currents depend on the frame of reference?

Do electric currents depend on the frame of reference?

Yes, electric currents can depend on the frame of reference. This is because the motion of charges that constitute the current can be perceived differently depending on the observer's frame of reference. According to the principles of special relativity, the observed current can change if the observer is moving relative to the charges.

How does special relativity affect the perception of electric currents?

Special relativity introduces the concept that the laws of physics, including electromagnetism, are the same in all inertial frames of reference. This means that an electric current observed in one frame of reference might be seen differently in another frame that is moving relative to the first. For example, a magnetic field in one frame can be transformed into an electric field in another frame, and vice versa.

Can an observer in a different frame of reference measure a different current in the same wire?

Yes, an observer moving relative to the wire can measure a different current. This is because the relative motion can alter the density and velocity of the charge carriers as seen by the observer. The Lorentz transformation equations from special relativity describe how these quantities change between different frames of reference.

What is the role of Lorentz transformation in understanding electric currents in different frames of reference?

The Lorentz transformation equations are crucial for understanding how electric and magnetic fields transform between different inertial frames of reference. These transformations help predict how quantities like electric current and charge density will appear to observers moving at different velocities relative to the system being studied.

Are there practical examples where frame of reference changes affect electric currents?

Yes, practical examples include scenarios in high-speed particle accelerators and astrophysical phenomena where relative velocities are significant. In such cases, the relative motion between observers and charged particles can lead to different measurements of currents and electromagnetic fields, demonstrating the importance of considering relativistic effects.

Similar threads

Replies
15
Views
2K
Replies
2
Views
879
Replies
20
Views
3K
Replies
5
Views
1K
Replies
2
Views
2K
Replies
7
Views
2K
Replies
1
Views
1K
Back
Top