- #1
Phymath
- 184
- 0
well while I am assuming I am just an idiot and this is wrong check it out...
[tex] \lambda = \frac{h}{p}[/tex]
[tex] c = f \lambda[/tex]
[tex]p = \frac{hf}{c}[/tex]
[tex] \frac{c}{f} = \lambda = \frac{h}{p}[/tex]
[tex]\frac{c}{f} = \frac{h}{mv} [/tex] v = c for a photon..
[tex] m = \frac{fh}{c^2}[/tex]->[tex] m = \frac{E}{c^2}[/tex]
while this is most likely hugely flawed it brings me to a question...if momentum of a photon is the above 3rd orginal equation, the momentum would increase as the frequency increases, and sense any EM radiation v = c the "mass" of the photon would have to change in a classical view p = mv so...whos to say that photons of all frequencies must have the same mass? let me know what everyones think'n!
[tex] \lambda = \frac{h}{p}[/tex]
[tex] c = f \lambda[/tex]
[tex]p = \frac{hf}{c}[/tex]
[tex] \frac{c}{f} = \lambda = \frac{h}{p}[/tex]
[tex]\frac{c}{f} = \frac{h}{mv} [/tex] v = c for a photon..
[tex] m = \frac{fh}{c^2}[/tex]->[tex] m = \frac{E}{c^2}[/tex]
while this is most likely hugely flawed it brings me to a question...if momentum of a photon is the above 3rd orginal equation, the momentum would increase as the frequency increases, and sense any EM radiation v = c the "mass" of the photon would have to change in a classical view p = mv so...whos to say that photons of all frequencies must have the same mass? let me know what everyones think'n!
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