- #1
klw289
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Two photons are moving in opposite directions along the y-axis are in the entangled polarization state
|Ψ> = (1/√2)(|VV>+|HH>)
V is vertical polarization relative to the z axis and measured from an axis n1 and is defined as θ=θ1 and H is horizontal polarization to the z axis measured from an axis n2 and is defined as θ=θ2.
Would PVV+PHH+PVH+PHV=1
If PVV is the probability that photon 1 givees vertical polarization relative to an axis n1 and photon 2 gives vertical polarization relative to an axis n2
Am I correct in saying this as there is no way to predict the outcome of a spin measurement and so those probabilities must add to one as they are all the options available and the choice of axis does not matter??
|Ψ> = (1/√2)(|VV>+|HH>)
V is vertical polarization relative to the z axis and measured from an axis n1 and is defined as θ=θ1 and H is horizontal polarization to the z axis measured from an axis n2 and is defined as θ=θ2.
Would PVV+PHH+PVH+PHV=1
If PVV is the probability that photon 1 givees vertical polarization relative to an axis n1 and photon 2 gives vertical polarization relative to an axis n2
Am I correct in saying this as there is no way to predict the outcome of a spin measurement and so those probabilities must add to one as they are all the options available and the choice of axis does not matter??