- #1
Phymath
- 184
- 0
in a case were we use a lot of inital velocity, does the projectiles equations
([tex]x = x_0 + v_0t + \frac{1}{2}at^2[/tex]) still hold I mean when its range is so large that it actually will go beyond the horizon? How does the equation compensate for a rounded surface or does it not have to? btw how far is the horizon for an average humans height, how do u figure that out for a given height?
([tex]x = x_0 + v_0t + \frac{1}{2}at^2[/tex]) still hold I mean when its range is so large that it actually will go beyond the horizon? How does the equation compensate for a rounded surface or does it not have to? btw how far is the horizon for an average humans height, how do u figure that out for a given height?