- #1
evinda
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MHB
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Hello! (Smile)
I want to find the rank of an elliptic curve.
To do so, I have to check if the following equations have a solution in $\mathbb{Z}$ with $x \cdot y \neq 0$.
$$\\z^2=x^4-4p^2y^4\\z^2=-x^4+4p^2y^4\\z^2=2x^4-2p^2y^4\\z^2=-2x^4+2p^2y^4\\z^2=4x^4-p^2y^4\\z^2=-4x^4+p^2y^4\\z^2=px^4-4py^4\\z^2=-px^4+4py^4\\ z^2=p^2x^4-4y^4\\z^2=-p^2x^4+4y^4\\ z^2=2px^4-2py^4\\z^2=-2px^4+2py^4\\ z^2=4px^4-py^4\\ z^2=-4px^4+py^4\\ z^2=2p^2x^4-2y^4\\ z^2=-2p^2x^4+2y^4\\ z^2=4p^2x^4-y^4\\ z^2=-4p^2x^4+y^4 $$
I think that the only two equations that have a solution in $\mathbb{Z}$ with $x \cdot y \neq 0$ are these: $z^2=2px^4-2py^4$ and $z^2=-2px^4+2py^4$.Am I right? (Thinking)Is there a criterion that we could use in order to determine if there is a solution?
I want to find the rank of an elliptic curve.
To do so, I have to check if the following equations have a solution in $\mathbb{Z}$ with $x \cdot y \neq 0$.
$$\\z^2=x^4-4p^2y^4\\z^2=-x^4+4p^2y^4\\z^2=2x^4-2p^2y^4\\z^2=-2x^4+2p^2y^4\\z^2=4x^4-p^2y^4\\z^2=-4x^4+p^2y^4\\z^2=px^4-4py^4\\z^2=-px^4+4py^4\\ z^2=p^2x^4-4y^4\\z^2=-p^2x^4+4y^4\\ z^2=2px^4-2py^4\\z^2=-2px^4+2py^4\\ z^2=4px^4-py^4\\ z^2=-4px^4+py^4\\ z^2=2p^2x^4-2y^4\\ z^2=-2p^2x^4+2y^4\\ z^2=4p^2x^4-y^4\\ z^2=-4p^2x^4+y^4 $$
I think that the only two equations that have a solution in $\mathbb{Z}$ with $x \cdot y \neq 0$ are these: $z^2=2px^4-2py^4$ and $z^2=-2px^4+2py^4$.Am I right? (Thinking)Is there a criterion that we could use in order to determine if there is a solution?