Does Commutativity Hold for Matrices A and B with a Specific Matrix C?

  • MHB
  • Thread starter TheScienceAlliance
  • Start date
  • Tags
    Matrix
In summary, the conversation discusses a construction proof involving matrices A, B, and C, where C is a 2x2 matrix with specific values in its first and second rows. It is shown that if AC = CA and BC = CB, then AB = BA. This is demonstrated by manipulating the values in A and B to show that they satisfy the condition for AB = BA.
  • #1
TheScienceAlliance
6
0
If A and B are matrices that AC = AC and BC=CB, where C is a matrix whose first row's entries are 0 1 and the second row's entries are -1 0, then AB=BA.
 
Mathematics news on Phys.org
  • #2
MathHelpBoardsUser said:
If A and B are matrices that AC = AC and BC=CB, where C is a matrix whose first row's entries are 0 1 and the second row's entries are -1 0, then AB=BA.
Is there a typo? Did you mean AC = CA?

-Dan
 
  • #3
topsquark said:
Is there a typo? Did you mean AC = CA?

-Dan
Yes. I apologize.
 
  • #4
Okay, so this is more or less a construction proof. You know that
\(\displaystyle C = \left ( \begin{matrix} 0 & 1 \\ -1 & 0 \end{matrix} \right )\)

Let
\(\displaystyle A = \left ( \begin{matrix} a & b \\ c & d \end{matrix} \right )\)

and
\(\displaystyle B = \left ( \begin{matrix} w & x \\ y & z \end{matrix} \right )\)

So.
1) Using AC = CA show that
\(\displaystyle A = \left ( \begin{matrix} a & b \\ -b & a \end{matrix} \right )\)

2) Using BC = CB show that
\(\displaystyle B = \left ( \begin{matrix} w & x \\ -x & w \end{matrix} \right )\)

3) Using A and B from 1) and 2) show that AB = BA.

-Dan
 

FAQ: Does Commutativity Hold for Matrices A and B with a Specific Matrix C?

What is the "Matrix: True or False? AB=BA" question?

The "Matrix: True or False? AB=BA" question is a mathematical question that asks whether the product of two matrices, AB, is equal to the product of the same matrices in reverse order, BA. In other words, does the order of multiplication matter in matrix multiplication?

Why is the "Matrix: True or False? AB=BA" question important?

This question is important because it tests the commutative property of matrix multiplication. If AB=BA is true, then matrix multiplication is commutative, meaning that the order of multiplication does not affect the result. This has significant implications in various fields, including physics, engineering, and computer science.

What is the answer to the "Matrix: True or False? AB=BA" question?

The answer to this question is that it depends on the matrices being multiplied. In general, matrix multiplication is not commutative, and AB does not equal BA. However, there are certain special cases where AB=BA is true, such as when one of the matrices is the identity matrix or when the matrices commute with each other.

How can I determine if AB=BA is true for a specific set of matrices?

To determine if AB=BA is true for a specific set of matrices, you can simply perform the matrix multiplication and compare the results. If the two products are equal, then AB=BA is true. If they are not equal, then AB=BA is false.

What are some real-world applications of the "Matrix: True or False? AB=BA" question?

The "Matrix: True or False? AB=BA" question has many real-world applications. In physics, it is used to calculate the moment of inertia of an object. In engineering, it is used in structural analysis and control systems. In computer science, it is used in graphics rendering and machine learning algorithms. Understanding the commutative property of matrix multiplication is essential in these fields to ensure accurate and efficient calculations.

Similar threads

Replies
1
Views
810
Replies
5
Views
2K
Replies
1
Views
2K
Replies
25
Views
1K
Replies
4
Views
1K
Replies
16
Views
3K
Replies
2
Views
1K
Replies
1
Views
967
Back
Top