MHB Does Compactness Ensure a Positive Minimum for Continuous Functions?

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Let $K \subset \mathbb{R^n}$ be compact and let $f: K \rightarrow \mathbb{R}$ be continuous. Suppose that $f(x) > 0$ $\forall x \in S.$ Prove there is a $c > 0$ such that $f(x) \geq c$ $\forall x \in K$

My Sol:

I said that by the extreme value theorem $\exists a,b \in K $ such that $f(a) \leq f(x) \leq f(b) \forall x\in K$ so if we let $c=f(a) $ then $c> 0$ and $f(x) \geq c$ a number c > 0 such that f(x) ≥ c for every x ∈ K
 
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Hi kalvin,

Assuming $S = K$, your solution is correct.
 
I posted this question on math-stackexchange but apparently I asked something stupid and I was downvoted. I still don't have an answer to my question so I hope someone in here can help me or at least explain me why I am asking something stupid. I started studying Complex Analysis and came upon the following theorem which is a direct consequence of the Cauchy-Goursat theorem: Let ##f:D\to\mathbb{C}## be an anlytic function over a simply connected region ##D##. If ##a## and ##z## are part of...
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