Does Core Material Influence the H-Field in a Toroidal Coil?

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In summary, the H-field depends on both free and bound currents, and in the example of a toroid with a ferromagnetic core and air gap, the H-field is much greater within the gap due to the contribution from the divergence of the magnetization. This is because the effect of the magnetic field is mostly canceled by the magnetization within the ferromagnetic material.
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Papikoss
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H-field depends on core material of toroid?

If I got this right, the H-field does not depend on the material it is applied on and is only determined by its sources (free currents).

So, suppose that we have a toroidal coil and some undefined core. As far as the H-filed is concerned, it would not make a difference if that core was air, a ferromagnetic material or some combination of those two. The H-field would remain the same.

However, if we apply Ampere's Law to a simple magnetic circuit, consisting of a ferromagnetic coil toroid having a small air gap, the result would be (taken from theory):

HfLf + HgLg = NI, where f, g refer to ferromagnetic material and air gap respectively.

Obviously here Hg is much greater than Hf

Now I'm confused! I know that the magnetic flux must remain constant throughout the circuit, but still I can't grasp how Hg and Hf could be different (the distribution of free currents did not change)!

Any help much appreciated!
 
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Papikoss said:
If I got this right, the H-field does not depend on the material it is applied on and is only determined by its sources (free currents).

No, this is not true except in special cases (despite what my not-quite-up-to-speed EM lecturer once tried to tell me!). If you have David Griffith's electromagnetism textbook, then he addresses this point in Section 6.3.2, "A Deceptive Parallel". The point he makes is that a vector field like H is specified by giving its curl and divergence at every point in space. The curl [itex]\nabla \times \mathbf{H}[/itex] is indeed determined by the free current, by Ampere's Law [itex]\nabla \times \mathbf{H} = \mathbf{J}_f[/itex], but divergence [itex]\nabla \cdot \mathbf{H}[/itex] is not. In the absence of magnetic materials, H has zero divergence, but otherwise it might not.
 
  • #3
Thank you for widening my horizons! Let’s see if I got this right this time:

The magnetic field depends both on free and bound currents.

In the example above (toroid with a ferromagnetic core, having a small gap) we can assume uniform magnetization within the core region, so no bound current density can be present, as is deducted from: [itex]\nabla\times\mathbf{M} = \mathbf{J}_b[/itex]

However, this is not the case with bound currents on the surface of the core, having a distribution similar to the distribution of the free currents and contributing to the final magnetic field.

Now if we assume a constant magnetic flux throughout the magnetic circuit (and a constant cross-sectional area) then the magnitude of magnetic flux density B is a constant too.

So within the ferromagnetic material it is :

[tex]\Large\mathbf{H}_f = \frac{\mathbf{B}}{\mu_0} - \mathbf{M}[/tex]

And within the gap area, where no magnetization applies,

[tex]\Large\mathbf{H}_g = \frac{\mathbf{B}}{\mu_0}[/tex]

Apparently, [itex]\mathbf{H}_g\gg\mathbf{H}_f[/itex].

Is that whole approach correct?

Thanks in advance!

PS How can I change the LaTeX font size of the whole document to Large?
 
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  • #4
Yes, the H field inside the ferromagnetic material is much smaller because the effect of the B field is mostly canceled by the magnetization. In particular, if we forget about non-linearity, hysteresis, etc., and just assume the material is characterized by a large magnetic susceptibility [itex]\chi_m[/itex], then we get

[tex]
H_f = \frac{1}{1 + \chi_m}\frac{B}{\mu_0} \ll \frac{B}{\mu_0} = H_g
[/tex]

Another way of thinking about this, in light of your original question, is that, in addition to the free current, there is a contribution to H from the divergence of the magnetization M (since [itex]\nabla \cdot \mathbf{H} = -\nabla \cdot \mathbf{M}[/itex]). The only place that M has nonzero divergence is at the edge of the gap, so this part of the H field is like the electric field from a parallel-plate capacitor. Thus the H field is much greater inside the gap due to this contribution.
 
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  • #5


I would say that the H-field does indeed depend on the material it is applied on, but it is not the only factor that determines its strength. The core material of a toroid can affect the H-field in a few ways. First, the permeability of the core material can affect the overall magnetic flux and thus the strength of the H-field. Second, the core material can also affect the distribution of free currents within the toroid, which in turn can affect the H-field. Additionally, the presence of an air gap in the magnetic circuit can also affect the H-field, as seen in the equation provided. Therefore, while the sources of the H-field may remain constant, the material and structure of the core can still have an impact on its strength and distribution.
 

FAQ: Does Core Material Influence the H-Field in a Toroidal Coil?

1. How does the material affect the H-field?

The H-field, or magnetic field, is affected by the material it passes through. This is because different materials have different permeability, which is a measure of how easily a material can be magnetized. Materials with higher permeability will allow the H-field to pass through more easily, while materials with lower permeability will resist the H-field and cause it to change direction.

2. What is the relationship between the H-field and the material's permeability?

The H-field is directly proportional to the material's permeability. This means that the higher the permeability of a material, the stronger the H-field will be in that material. Conversely, a material with lower permeability will have a weaker H-field.

3. Can the H-field be manipulated by changing the material?

Yes, the H-field can be manipulated by changing the material it passes through. By using materials with different permeability, the strength and direction of the H-field can be altered. This is often used in electromagnets, where the strength of the magnetic field can be controlled by adjusting the material's permeability.

4. How does the H-field interact with different types of materials?

The H-field can interact with different types of materials in various ways. Materials with high permeability, such as iron or nickel, will attract the H-field and become magnetized. Other materials, such as copper or aluminum, have low permeability and will not be affected by the H-field. Some materials, like superconductors, can completely block the H-field from passing through.

5. Can the H-field have a different effect on different materials?

Yes, the H-field can have different effects on different materials. This is because materials have different magnetic properties, which can affect how they respond to the H-field. For example, some materials may become magnetized in the presence of the H-field, while others may experience a repulsive force. The strength of the H-field can also vary depending on the material, resulting in different levels of magnetization or resistance.

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