- #1
azaharak
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One form of bernoullis equation (fluid flow) incompressible is
the change in pressure plus [the change in (velocity squared)*density/2] = 0
when the height of the fluid remains the same.
This along with the continuity of mass A1v1=A2v2 allows you to infer that decreasing the volume of a given pipe would result in a higher speed of fluid flow (incompressible).
This would in turn result in a pressure drop if you plugged it into bernoullis equation?
Is this valid reasoning? Just because the fluid is moving faster doesn't mean the pressure is greater in the thinner pipe?
If this is so, then there are many bad claims on the internet that squeezing a hose results in a larger pressure? Or blood through thinner veins results in higher pressure?
Thanks for any comments
Best
the change in pressure plus [the change in (velocity squared)*density/2] = 0
when the height of the fluid remains the same.
This along with the continuity of mass A1v1=A2v2 allows you to infer that decreasing the volume of a given pipe would result in a higher speed of fluid flow (incompressible).
This would in turn result in a pressure drop if you plugged it into bernoullis equation?
Is this valid reasoning? Just because the fluid is moving faster doesn't mean the pressure is greater in the thinner pipe?
If this is so, then there are many bad claims on the internet that squeezing a hose results in a larger pressure? Or blood through thinner veins results in higher pressure?
Thanks for any comments
Best