Does intensity determine the occurrence of the photoelectric effect?

In summary, the photoelectric effect requires a minimum frequency, or threshold frequency, of the incident radiation in order to emit an electron. This is because the electron needs a minimum amount of energy, called the work function, to repulse the intermolecular forces. Increasing the intensity of the radiation does not necessarily increase the energy supplied to the electron, as the energy must come in one shot. It is possible for a photon with a frequency below the threshold to eject an electron through a multi-photon process, but this is rare in natural atoms. However, in artificial systems, such as quantum wells, multiple photons can add up to reach the threshold. Additionally, at high intensities, the radiation can perturb the potential and shift the position
  • #1
rohanprabhu
414
2
For the photoelectric effec to take place for a certain metal, there is a minimum frequency that the incident radiation must have, also called the threshold frequency. Let us call it [itex]f_o[/itex].

The electron is emmitted only when a minimum amount of energy is provided to it so that it can repulse the intermolecular forces. This energy, called the 'Work function' is [itex]\phi = f_o[/itex] [where 'h' is the Planck's constant].

Now, if the minimum energy is not provided, the electron is not emitted. No matter how high the intensity of the incident radiation is, the electron won't be emitted unless the radiation has a frequency [itex]f_o[/itex].

But, if it is energy dependent, won't increasing the Intensity increase the energy too? Because,

[tex] I = \frac{dP}{dA}[/tex]

Therefore, if a radiation has a higher intensity, won't it be having a higher value of Power? Which means that the energy supplied per unit time should also be higher. So, for a higher value of Intensity, the energy is more... So why doesn't it show the photoelectric effect unless and until the metal is irradiated with a radiation having a frequency of [itex]f_o[/itex]
 
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  • #2
the thing is that the energy must come in ONE shot, the electron can't "gather energy".

The energy of a photon is given by its frequency, so you must have a frequency above a certain threshould. The energy of the beam is not the interesting thing, it is the energy of a the individual photons.
 
  • #3
malawi_glenn said:
the thing is that the energy must come in ONE shot, the electron can't "gather energy".

The energy of a photon is given by its frequency, so you must have a frequency above a certain threshould. The energy of the beam is not the interesting thing, it is the energy of a the individual photons.

ok.. so do you mean to say that an electron is ejected only when it annihilates a photon with the threshold frequency?
 
  • #4
yes, that is correct. (or higher frequency)
 
  • #5
It is preumably possible to eject a photon even when the frequency is lower than the "threshold" using a multi-photon process. Two photon processes -where each photon has half the energy- are quite common and are used in spectroscopy. 3 photon processes are rare and higher order processes are as far as I know almost negligle in natural atoms (but can be seen in spectroscopy on e.g. Rydberg atoms). However, there are artifical systems ("quantum well") where tens of photons can "add up" (I think the highest I have ever seen is 13), the probability for such processes increases quite a lot in strongly anharmonic potentials.

Also, the intensity of the radiation DOES matter if it is very high. The reason is simply that the radiation itself can perturb the potential in such a way that the position of the levels are shifted; it is therefore possible to "hit" the resonance simply by driving the system very hard. Due to "ladder" process with virtual levels it is therefore possible to excite systems even when starting far from resonance if the drive amplitude is high enough. Unfortunately, the physics is VERY complicated since these processes can't be treated using perturbation theory and AFAIK there is no "simple" theory.
 
  • #6
f95toli said:
It is preumably possible to eject a photon even when the frequency is lower than the "threshold" using a multi-photon process. Two photon processes -where each photon has half the energy- are quite common and are used in spectroscopy. 3 photon processes are rare and higher order processes are as far as I know almost negligle in natural atoms (but can be seen in spectroscopy on e.g. Rydberg atoms). However, there are artifical systems ("quantum well") where tens of photons can "add up" (I think the highest I have ever seen is 13), the probability for such processes increases quite a lot in strongly anharmonic potentials.

Also, the intensity of the radiation DOES matter if it is very high. The reason is simply that the radiation itself can perturb the potential in such a way that the position of the levels are shifted; it is therefore possible to "hit" the resonance simply by driving the system very hard. Due to "ladder" process with virtual levels it is therefore possible to excite systems even when starting far from resonance if the drive amplitude is high enough. Unfortunately, the physics is VERY complicated since these processes can't be treated using perturbation theory and AFAIK there is no "simple" theory.

of course more elaborate discussions about the photo electric effect can be made, but this has not so much to do what the OP asked about. He doubted the very basics about the photo eletric effect.
 
  • #7
malawi_glenn said:
of course more elaborate discussions about the photo electric effect can be made, but this has not so much to do what the OP asked about. He doubted the very basics about the photo eletric effect.

OP??

another question is.. If there is a photon having a frequency higher than [itex]f_o[/itex], but not high enough so that the electron can accept it all [afaik, an electron can accept only a set of particular amounts of energy].. so is this remaining energy rejected? If it is rejected.. does it result in the creation of a new photon of a frequency such that it's energy is the energy difference between the nearest quanta of energy the electron could accept and the one brought in by the incident photon?
 
  • #8
op = original poster.

if the photons energy is not not enough to remove the electron from the atom, it can do other things, for example excite an atom or heat the solid etc.
 
  • #9
rohanprabhu said:
OP??

another question is.. If there is a photon having a frequency higher than [itex]f_o[/itex], but not high enough so that the electron can accept it all [afaik, an electron can accept only a set of particular amounts of energy].. so is this remaining energy rejected? If it is rejected.. does it result in the creation of a new photon of a frequency such that it's energy is the energy difference between the nearest quanta of energy the electron could accept and the one brought in by the incident photon?

This is not correct. If the photon energy is larger than the threshold, then the "extra" energy is the kinetic energy of the emitted electron. That is why you see a spectrum of energy for all the photoelectrons emitted.

Zz.
 
  • #10
"If there is a photon having a frequency higher than , but not high enough so that the electron can accept it all " Seems like a condradiction.
 
  • #11
ZapperZ said:
This is not correct. If the photon energy is larger than the threshold, then the "extra" energy is the kinetic energy of the emitted electron. That is why you see a spectrum of energy for all the photoelectrons emitted.

Zz.

forget about the photoelectric effect for a moment. What about the electrons jumping orbits? If it receives photons that can make it jump to the 2nd orbit + a little extra energy, but not enough to make it jump till the 3rd.. does it reject it completely or reject just a part of it?

my teacher told me that it rejects it completely.. though I'm a bit reluctant to agree to that?
 
  • #12
it rejects it when chaning orbits yes.

But imagine the photo electric effect as ionization, the ionization energy of H is 13.6eV, if a photon of E = 20eV enters, the electron will be emitted with 6.4eV kinetic energy. The excitation energy for n=1 to n=2 is 10.4eV, and if the incoming photon has energy 11eV, then it can not excite the electron to that orbit, it does not interact with the atom at all here.
 
  • #13
malawi_glenn said:
it rejects it when chaning orbits yes.

But imagine the photo electric effect as ionization, the ionization energy of H is 13.6eV, if a photon of E = 20eV enters, the electron will be emitted with 6.4eV kinetic energy. The excitation energy for n=1 to n=2 is 10.4eV, and if the incoming photon has energy 11eV, then it can not excite the electron to that orbit, it does not interact with the atom at all here.

thx a lot man.. it helped me understand a lot today :D

/offtopic: are u on this forum all day long?? :P
 
  • #14
I have nothing elso to do man ;) Shall ask some questions here my self, so I want to contribute to this lovley forum by giving answers to something that I understand :P
 
  • #15
malawi_glenn said:
it rejects it when chaning orbits yes.

But imagine the photo electric effect as ionization, the ionization energy of H is 13.6eV, if a photon of E = 20eV enters, the electron will be emitted with 6.4eV kinetic energy. The excitation energy for n=1 to n=2 is 10.4eV, and if the incoming photon has energy 11eV, then it can not excite the electron to that orbit, it does not interact with the atom at all here.

How about a photon with 20.8eV of energy? Any difference?
 
  • #16
dst said:
How about a photon with 20.8eV of energy? Any difference?

energy is still too high right?.. ;)
 

Related to Does intensity determine the occurrence of the photoelectric effect?

1. What is the photoelectric effect?

The photoelectric effect is a phenomenon in which light of a certain frequency (or above) causes the ejection of electrons from a material. This was first discovered by physicist Albert Einstein in 1905.

2. What causes the photoelectric effect?

The photoelectric effect occurs when photons (particles of light) bombard a material and transfer their energy to electrons within the material. The electrons then gain enough energy to break free from the material's surface and become photoelectrons.

3. How does the frequency of light affect the photoelectric effect?

The frequency of light is directly related to the energy of the photons. The higher the frequency of light, the higher the energy of the photons. Therefore, only light with a frequency above a certain threshold frequency can cause the photoelectric effect, as it provides enough energy to eject electrons from the material.

4. What is the work function in relation to the photoelectric effect?

The work function is the minimum amount of energy needed for an electron to escape the material. It is different for each material and is a key factor in determining the threshold frequency for the photoelectric effect. The work function is also used to calculate the maximum kinetic energy of the photoelectrons.

5. What are the applications of the photoelectric effect?

The photoelectric effect has various applications in modern technology, such as solar panels, photodiodes, and photocells. These devices use the photoelectric effect to convert light energy into electrical energy. The photoelectric effect also plays a crucial role in the functioning of digital cameras and night vision goggles.

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