- #36
mieral
- 203
- 5
vanhees71 said:Have you ever read a real textbook on QT? To write down the most simple Hamiltonian in atomic physics (the hydrogen atom) you need already momentum:
$$\hat{H}=\frac{\hat{\vec{p}}_1^2}{2m} + \frac{\hat{\vec{p}}_2^2}{2M} -\frac{e^2}{4 \pi |\hat{\vec{x}}_1 - \hat{\vec{x}}_2|}.$$
Here ##\vec{p}_1## and ##\vec{p}_2## are the momenta of the electron and the proton and ##\hat{\vec{x}}_1## and ##\hat{\vec{x}}_2## their position vectors, respectively.
While it is generally agreed potential is independent of momentum. But how come potential+kinetic is no longer independent to momentum as you showed above?
Yes, in my expression the potential is indeed independent of momentum, it's the Coulomb potential between two point particles. I can only again strongly advice to go back and first learn classical mechanics up to and including the Hamiltonian formulation. The goal must be to have a very good understanding of Poisson brackets and basics of Lie algebras and groups. Then you can attach quantum theory again, e.g., with a textbook like Sakurai.
What you mean it's the Coulomb potential between two point particles? Why did you include Coulomb here.
Yes. I agree I need to first get good handle of classical mechanics up to and including the Hamiltonian formulation. What would be a good book about this.
To solve the energy eigenvalue problem, what you indeed only need to know are the commutation relations between these quantities. Pauli solved the hydrogen problem within matrix mechanics by knowing the classical physics of the problem very well, making use of the large dynamical symmetry and the Runge-Lenz vector.
Schrödinger solved the same problem, using his wave mechanics, which was more within the mathematical standard techniques of the physicists at his time, i.e., he wrote down the energy eigenvalue problem in terms of the partial differential equation, which we now call the "time-independent Schrödinger equation". For this he needed to know that in the position representation the momentum operators are ##\hat{\vec{p}}_1=-\mathrm{i} \hbar \vec{\nabla}_1## etc.