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vanesch
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mn4j said:Thanks for mentioning this. I wasn't aware of this paper as they only cite the original paper in a footnote( difficult to track). However, this paper is hardly a rebutt. I'll characterise it as a "musing". After reading this paper I believe the author has misunderstood the work of Hess and Philipp, probably based on a basic misunderstanding of probability theory. The author claims he is working on a detailed rebutt of Hess and Philipp. I'm waiting to read that.
There have however been other disproofs of Bell's theorem independent of Hess and Philipp:
* Disproof of Bells theorem by Clifford Algebra Valued Local Variables. http://arxiv.org/pdf/quant-ph/0703179.pdf
* Disproof of Bell's Theorem: Reply to Critics. http://arxiv.org/pdf/quant-ph/0703244.pdf
* Disproof of Bell's Theorem: Further Consolidations. http://arxiv.org/pdf/0707.1333.pdf
These are sophisticated ways of saying that they didn't understand what Bell was claiming. The simplest form of Bell's theorem can be found by selecting simply 3 angular directions. As such, no sophisticated modelling, no Clifford or other algebras, simply the following:
Consider 3 angular settings, A, B and C.
Now, give me, as a model, the "hidden variable" probabilities for the 8 possible cases:
hidden state "1" : A = down, B = down, C = down ; probability of hidden state 1 = p1
hidden state "2": A = down, B = down, C = up ; probability of hidden state 2 = p2
hidden state "3": A = down, B = up, C = down ; probability of hidden state 3 = p3
...
hidden state "8" : A = up , B = up, C = up ; probability of hidden state 8 = p8.
In the above, "A = down" means: in the hidden state that has A = "down", we will measure, with certainty, a "down" result if observer 1 applies this hidden = state to a measurement in the direction "A".
Because there is perfect anti-correlation when observer 1 and observer 2 measure along the same direction, we can infer that A = down means that when this state is presented to observer 2, he will find with certainty the "up" result if he measures along the axis A.
You don't need to give me any "mechanical model" that produces p1, ... p8. Just the 8 numbers, such that 1 > p1 > 0 ; 1 > p2 > 0 ... ; 1 > p8 > 0, and p1 + p2 + ... + p8 = 1 ; in other words, {p1,... p8} form a probability distribution over the universe of the 8 possible hidden states which interest us.
If we apply the above hidden variable distribution to find the correlation between the measurement by observer 1 along A, and by observer 2 along B, we find:
for hidden state 1: correlation = -1 (obs. 1 finds down, obs. 2 finds up)
for hidden state 2: correlation = -1
for hidden state 3: correlation = 1 (both find down)
for hidden state 4: correlation = 1 (both find down)
for hidden state 5: correlation = 1 (both find up)
for hidden state 6: correlation = 1 (both find up)
for hidden state 7: correlation = -1
for hidden state 8: correlation = -1.
So we find that the correlation is given by
C(A,B) = p3 + p4 + p5 + p6 - p7 - p8 -p1 - p2
We can work out, that way:
C(A,C)
C(B,A)
C(B,C)
C(C,A)
and
C(C,B).
They are sums and differences of the numbers p1 ... p8.
Well, the point of Bell's theorem is that you cannot find 8 such numbers p1, p2, ...
which give the same results for C(X,Y) as do the quantum predictions for C(X,Y) when the directions are 0 degrees, 45 degrees and 90 degrees (for a spin-1/2 system).
So you can find the most sophisticated model you want. In the end, you have to come up with 8 numbers p1, ... p8, which are probabilities. And then you cannot obtain the quantum correlations. The model doesn't matter. You don't even need a model. You only need 8 numbers. And you can't give them to me, because they don't exist.
If you think you have a model that shows that Bell was wrong, give me the 8 probabilities p1, ... p8 you get out of it and show me how they give rise to the quantum correlations.
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