Does the Conservation of Energy Apply to Rotating Wheels Connected in a Series?

In summary: I was right!In summary, Hypo's question is asking if 1000J of energy will be divided equally between two or three rotating wheels connected to a power supply. If the wheels are connected from the start, then each wheel will receive 500J. If one of the wheels is disconnected, then the remaining two wheels will each receive 500J.
  • #1
Hypo
59
0
Hallo everyone.

I had a equation about energy in a form of "rotational kinetic energy".

Imagine this situation with me so I can explain the question I'm trying to get at:

Let say I had a rotating wheel that is connected to other wheels directly... I supplied 1000J(simple number for me to understand clear) to the wheel for it to spin!(Try to ignore energy loss).

So 1000J is converted from kinetic energy to rotational kinetic energy... Let's say I had two wheels connected to the main wheel that's supplying 1000J of energy will that energy be divided into by 2? 500 and 500?

And obviously if 1 wheel's connected with no energy loss it will convert the 1000J directly right? If so please give out a detailed reason why both of those wheel can't get 1000J? I feel confused because "WORK" is mind bothering!

*NOTE: Ignore energy loss for a bit please let's keep this all under the realm of"theory".
 
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  • #2
Welcome to PF!

Hallo Hypo! Welcome to PF! :smile:
Hypo said:
Let say I had a rotating wheel that is connected to other wheels directly... I supplied 1000J(simple number for me to understand clear) to the wheel for it to spin!(Try to ignore energy loss).

So 1000J is converted from kinetic energy to rotational kinetic energy... Let's say I had two wheels connected to the main wheel that's supplying 1000J of energy will that energy be divided into by 2? 500 and 500?

And obviously if 1 wheel's connected with no energy loss it will convert the 1000J directly right? If so please give out a detailed reason why both of those wheel can't get 1000J? I feel confused because "WORK" is mind bothering!

I'm not sure what you mean by "supplying energy". :confused:

Suppose you supply 1000 J to the first wheel, then you disconnect the power supply.

Then you connect the first wheel to two other wheels in such a way that the first wheel stops, and all its energy goes into the other two.

Isn't it obvious that they get 500 J each? :confused:

(If all three wheels are connected from the start, I don't see how you can say you're supplying energy to the first wheel first, it's having to be shared between all three wheels)
 
  • #3
If you look at a system of rotating wheels, then the total kinetic energy (which is equal to the total rotational kinetic energy and total linear kinetic energy) of the system is the sum of the kinetic energy of each wheel. If the system starts with zero kinetic energy and you provide 1 kJ, then the kinetic energy of the system will be 1 kJ assuming that there are no frictional loss and that there are no increase in potential energy.

In order to find out how those 1 kJ is distributed on each wheel you must know more about their shape and mass. If you have two identical wheels directly connected such that they both rotate with same angular speed afterwards, then each wheel will have 500 J of rotational kinetic energy. In general, if the two directly connected wheels have moment of inertia around the axis of rotation of I1 and I2, then the rotational kinetic energy of each wheel is K1 = 1/2 I1ω2 and K2 = 1/2 I2ω2, where ω is the angular speed. Since total rotational kinetic energy is K = 1/2 (I1+I22 = 1 kJ the angular speed ω can be found from K and then inserted into the rotational kinetic energy for each wheel, giving K1 = K I1/(I1+I2) and K2 = K I2/(I1+I2). In other words, the ration of rotational kinetic energy of the wheels are K1/K2 = I1/I2.

You can find a list of moments of inertia for different shapes at [1].

[1] http://en.wikipedia.org/wiki/List_of_moments_of_inertia
 
  • #4
You also have to conserve angular momentum as well as energy. You cannot figure out how the energy will be shared unless you take into account that the angular momentum must be shared also. Then you can figure it out.

Suppose K is the rotational kinetic energy of the first wheel and M is the angular momentum of the first wheel. Then by conservation of energy, [tex]K=\tfrac{1}{2}I_1\omega_1^2+\tfrac{1}{2}I_2\omega_2^2[/tex] and by conservation of angular momentum, [tex]M=I_1\omega_1+I_2\omega_2[/tex] where subscripts 1 and 2 refer to the other two wheels. Using these two equations, you can find the two unknowns, [itex]\omega_1[/itex] and [itex]\omega_2[/itex]
 
  • #5
Thank you everyone.

Basic conclusion from all the formula's and laws is that energy is shared equally in the system if ALL the physical states are the same: Size, Mass, etc...

Sadly this is kinda of a burden because "Energy" is a complex process I think that limitless us in every way we go.

I believe their's more to study about "Energy". I thought for some reason in that system the 1000J will be given to all three wheels but I said to my self that's too good to be true.
 
  • #6


tiny-tim said:
Hallo Hypo! Welcome to PF! :smile:


Thanks Tim.
 
  • #7
Rap said:
You also have to conserve angular momentum as well as energy.

In this particular situation, where the OP increases the rotational energy of a system from zero to some value K presumably by applying a torque to a shaft, there is not conservation of angular momentum.
 
  • #8
The thing is... Can I notice a difference? I mean looking at the main wheel that supplies 1KJ spinning so so fast and looking at the identical wheels that are connected directly to it spinning fast as well thought they would get the same amount of speed + energy.

Now their is NO WAY they would get the same amount of energy right? I mean the 1KJ they will never get that amount unless I supplied more energy to the main wheel. The thing is I wonder the most about is for example when the wheel's are connected how is that energy exactly shared?

I'd like to imagine this clearly.
 
  • #9
Filip Larsen said:
In this particular situation, where the OP increases the rotational energy of a system from zero to some value K presumably by applying a torque to a shaft, there is not conservation of angular momentum.

Well, there is always conservation of angular momentum, I guess the question is whether it all goes to the other two wheels or not. I am having trouble picturing the mechanism, so I can't really say.
 
  • #10
Hypo said:
Now their is NO WAY they would get the same amount of energy right? I mean the 1KJ they will never get that amount unless I supplied more energy to the main wheel.

Correct. The rotational energy in the wheels have to come from somewhere, so if you provide 1 kJ then the wheels will increase their rotational energy with 1 kJ. If any of the energy you provide gets lost to friction or converted into potential energy then the increase in rotational energy of the wheels would be less than 1 kJ.

Hypo said:
The thing is I wonder the most about is for example when the wheel's are connected how is that energy exactly shared?

I have provided you with some equations in post #3 that show how rotational energy are distributed between two wheels in a simple system. Are you able to understand what I explain in that post? I assume in that post that you know about rotational energy, but if you don't you may want to read up on that concept. Wikipedia has a short introduction to the concept [2]. If that doesn't help you may want to pick up a textbook on introductory physics.


[2] http://en.wikipedia.org/wiki/Rotational_energy
 
  • #11
Rap said:
there is always conservation of angular momentum

In an isolated system (i.e. a system that does not exchange force (F = 0) or torque (N = 0) with its environment) you do indeed have conservation of momentum and angular momentum which follows from Newtons law [3] (dp/dt = F = 0) and Eulers law [4] (dL/dt = N = 0).

However, in this case you have a system of rotating bodies to which energy is provided from outside the system. If, the energy is provided to the system by a person applying torque N over time to to a shaft in the system in order to induce rotation in the system, then the change in angular momentum is equal to the torque (dL/dt = N) which means that angular momentum is not constant.


[3] http://en.wikipedia.org/wiki/Newton's_laws_of_motion
[4] http://en.wikipedia.org/wiki/Euler's_laws_of_motion
 
  • #12
Filip - ok, right. I was talking about a closed system, you are not. Again, there seems to be differing ideas of the OP.

1. Wheel 1 has energy 1000J and somehow transfers all of this energy to wheels 2a and 2b, with no dissipation or changes in potential energy. (closed system)

2. Wheel 1 is continually supplied energy, some of which is transferred to wheels 2a and 2b, until the total energy of wheels 2a and 2b is 1000J, again with no dissipation or changes in potential energy. (open system)

Any I missed? I was assuming case 1, you are assuming case 2. Can we first clarify what the OP is?
 
  • #13
Rap said:
I was assuming case 1, you are assuming case 2.

If you want to model the final energy state of the wheels you call 2a and 2b then it surely is most interesting to have a system boundary that includes those two wheels. In your case 1, wheel 1 is not rotating in the final state so it might as well be outside the system. By the way, in the model I used, there is no wheel 1; the energy and torque simply comes from an unspecified source outside the system of the two wheels 2a and 2b.

Also note, that in your case 1, even if you can say there is conservation of momentum it does not provide any extra information or constraint over conservation of energy since wheel 1 already has been specified to have 1 kJ of rotational energy before and zero afterwards, i.e. conservation of energy under the given circumstances alone specifies that the rotational energy of wheel 2a and 2b afterwards must equal to 1 kJ and, thus, their angular speed can be determined from conservation of energy alone. You could of course translate the rotational energy of wheel 1 into the equivalent angular momentum, use conservation of angular momentum and translate angular momentum back to rotational energy of wheel 2a and 2b, but since the OP (as I read it) is asking about the energy distribution between 2a and 2b you may as well stay with energy.
 
  • #14
Filip Larsen said:
Also note, that in your case 1, even if you can say there is conservation of momentum it does not provide any extra information or constraint over conservation of energy since wheel 1 already has been specified to have 1 kJ of rotational energy before and zero afterwards, i.e. conservation of energy under the given circumstances alone specifies that the rotational energy of wheel 2a and 2b afterwards must equal to 1 kJ and, thus, their angular speed can be determined from conservation of energy alone. You could of course translate the rotational energy of wheel 1 into the equivalent angular momentum, use conservation of angular momentum and translate angular momentum back to rotational energy of wheel 2a and 2b, but since the OP (as I read it) is asking about the energy distribution between 2a and 2b you may as well stay with energy.

Only if you assume that the angular velocity of 2a and 2b are equal, as you did, but which I do not find in the OP. Let's call the two wheels a and b, rather than 2a and 2b. Conservation of energy states that: [tex]\tfrac{1}{2}I_a\omega_a^2+\tfrac{1}{2}I_b\omega_b^2=1000J[/tex] and you cannot solve that single equation for the two angular velocities, nor the individual energies.
 
  • #15
Rap said:
Only if you assume that the angular velocity of 2a and 2b are equal, as you did, but which I do not find in the OP. Let's call the two wheels a and b, rather than 2a and 2b. Conservation of energy states that: [tex]\tfrac{1}{2}I_a\omega_a^2+\tfrac{1}{2}I_b\omega_b^2=1000J[/tex] and you cannot solve that single equation for the two angular velocities, nor the individual energies.

I agree that is not easy to extract the exact situation from that post and that you need another constraint to find exactly how the rotational energy is distributed between the two wheels, at which point I used equal angular velocity as a constraint to model a mechanical linkage between the two wheels and you used conservation of angular momentum as a constraint in the situation where three wheels are used.
 
  • #16
Hypo said:
Hallo everyone.

I had a equation about energy in a form of "rotational kinetic energy".

Imagine this situation with me so I can explain the question I'm trying to get at:

Let say I had a rotating wheel that is connected to other wheels directly... I supplied 1000J(simple number for me to understand clear) to the wheel for it to spin!(Try to ignore energy loss).

So 1000J is converted from kinetic energy to rotational kinetic energy... Let's say I had two wheels connected to the main wheel that's supplying 1000J of energy will that energy be divided into by 2? 500 and 500?

And obviously if 1 wheel's connected with no energy loss it will convert the 1000J directly right? If so please give out a detailed reason why both of those wheel can't get 1000J? I feel confused because "WORK" is mind bothering!

*NOTE: Ignore energy loss for a bit please let's keep this all under the realm of"theory".


Let us consider a train that is 100 coaches long.

The locomotive pulls with force 100 Newtons the first coach.
The first coach pulls with force 99 Newtons the second coach.
The second coach pulls with force 98 Newtons the third coach.

We observe that each coach causes a 1 Newtons decrease in the pulling force.

When a coach moves a distance of 1 meters, an energy of 1 Newtons * 1 meters turns into heat, if we have a non-accelerating train, or that much energy turns into kinetic energy of the coach, if the train is an accelerating train.
 

FAQ: Does the Conservation of Energy Apply to Rotating Wheels Connected in a Series?

Does the conservation of energy apply to rotating wheels connected in a series?

Yes, the conservation of energy applies to all systems, including rotating wheels connected in a series. This means that the total amount of energy in the system remains constant, and energy can only be transferred or transformed between different forms.

How does the conservation of energy apply to rotating wheels connected in a series?

In a system of rotating wheels connected in a series, the total amount of energy is conserved because the energy input into the system is equal to the energy output. This is known as the law of conservation of energy, which states that energy cannot be created or destroyed, only transformed.

What factors affect the conservation of energy in rotating wheels connected in a series?

The conservation of energy in rotating wheels connected in a series is affected by factors such as the speed and size of the wheels, the amount of friction present, and the efficiency of the system. In an ideal scenario with no friction, the conservation of energy would be perfectly preserved.

Can the conservation of energy be violated in a system of rotating wheels connected in a series?

No, the conservation of energy is a fundamental law of physics and cannot be violated. In a system of rotating wheels connected in a series, any changes in energy would be due to external factors, such as friction or external forces, and not a violation of the conservation of energy.

How is the conservation of energy in rotating wheels connected in a series relevant in real-life applications?

The conservation of energy in rotating wheels connected in a series is relevant in many real-life applications, such as in vehicles with multiple rotating wheels. Understanding and applying the conservation of energy helps engineers and scientists design more efficient systems and minimize energy loss, ultimately leading to more sustainable and cost-effective solutions.

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