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nycmathdad
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Verify the given function has a zero in the indicated interval. Then use the Intermediate Value Theorem to approximate the zero correct to three decimal places by repeatedly subdividing the interval containing the zero into 10 subintervals.
f (x) = x3 − 4x + 2; interval: (1, 2)
I don't understand the instructions. How is this done?
f (x) = x3 − 4x + 2; interval: (1, 2)
I don't understand the instructions. How is this done?