Does the Launch Angle Affect Efficiency in a Slingshot?

In summary: explanation for why, in our tests, the efficiency of our slingshot device remained constant when the angle of launch was changed and the extension (how far the rubber band was pulled back) was constant.
  • #1
donkeycopter
40
0
I need to explain why, in our tests, the efficiency of our slingshot device remained constant when the angle of launch was changed and the extension (how far the rubber band was pulled back) was constant.

Basically it was a 1m long wooden plank held up on bricks, with a rubber band attached to 2 nails at the top of the board. We put a rubber ball in the rubber band and shot it from different angles.

We calculate efficiency in terms of energy lost.

Thanks!
 
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  • #2
Well, what caused the energy loss?
 
  • #3
thanks for your reply!

See I've identified air resistance and friction between the ball and the plank as how the ball loses energy, but I don't really know. Why would that not be effected when the angle changes?
 
  • #4
shouldn't the weight vector down the plane effect the efficiency when angle is changed? Why does it not?
 
  • #5
Can you provide some more details, such as the weight of the ball (or how big it is, what material it is made of), the dimensions of the rubber band?
 
  • #6
[tex]\eta= \frac{Energy \ Output}{Energy \ Input}[/tex]

What is type of energy is the input (rubber band)?
Since the mass lands on the ground, the final energy at the ground is kinetic.
 
  • #7
The weight of the ball is 0.015g. It is a rubber bouncy ball. The rubber bands is about 15cm on each side.

Why doesn't the angle affect the efficiency?
 
  • #8
I think it does actually. If we consider the output energy is kinetic energy, then there are 2 factors making the ball lose its energy: friction and gravity (strictly speaking, there are 3, the other of which is air resistance; but it's trivial in this experiment).
However the output energy is nearly the same even though the angle changes. Here is the reason:
- The Young modulus of rubber is about E = 107 Pa. Suppose that the rubber band has width of 1cm, thickness of 1mm, then the elastic constant of this rubber band is about k=1333 N/m. If we stretch the rubber band from 15cm to 20cm (let's hope that Hooke's law still works!), then the elastic energy, or input energy, is Ei = 1.67 J.
- The ball goes through a distance of d=5cm (from 20cm to 15cm) before it leaves the rubber band. In the extreme case, where the plank is raised vertically, the energy lost to gravitational energy is Eg = mgd = 0.0075 J (I guess you meant m=0.015 kg or 15g).
- Friction on the ball F = rN, where r is the frictional coefficient and N is the normal force. In the extreme case, where the plank is set horizontally, N=mg. Suppose that r=1 (r=1 is very rare and very large too!). Therefore: F=0.15 N. The work done by friction when the ball leaves the rubber band: W = Fd = 0.0075 J.
You can see that W and Eg << Ei. That means, the energy lost is infinitesimal compared to the input energy, so output energy nearly equals to input energy. The efficiency is nearly 100%.
 
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  • #9
Thanks very much Hikaru!

The thing is, efficiency is about 40% in reality.

Why is air resistance trivial? I was under the impression that was the main component slowing the ball down?

I think you may have calculated the coefficient incorrectly, its closer to 200Nm that 1333.


But, as my tests show, the angle doesn't effect efficiency. Can anyone supply a good reason for this happening? I don't need explanations of what should happen - but why what's happened occurs!

Thanks! :)
 
  • #10
donkeycopter said:
I was under the impression that was the main component slowing the ball down?

I think you're right about it being the main component. But at what angle does air resistance act relative to projectile's velocity?

EDIT: I think this should have been my first response to you. Sorry if so.
 
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  • #12
but why does the angle not effect efficiency?

@rock.freak667: How is that relevant?
 
  • #13
donkeycopter said:
Thanks very much Hikaru!

The thing is, efficiency is about 40% in reality.

Why is air resistance trivial? I was under the impression that was the main component slowing the ball down?

I think you may have calculated the coefficient incorrectly, its closer to 200Nm that 1333.


But, as my tests show, the angle doesn't effect efficiency. Can anyone supply a good reason for this happening? I don't need explanations of what should happen - but why what's happened occurs!

Thanks! :)

Then how do you calculate efficiency anyway? I doubt it's not the slingshot's efficiency.
About the elastic coefficient, I use the standard value of rubber, which can be found on most websites. The material used to make the band is one factor. Another factor is the extension length. Hookes' law only applies to rubber in small range.
 
  • #14
I calculated efficiency as the real KE over the ideal KE.

But that's irrelevant, my teacher has confirmed my efficiencies are accurate!


What I need to know is a reason the angle doesn't effect the efficiency? Just a reason to describe this (if it is) anomaly?

Thanks!
 
  • #15
How do you calculate the real KE?
 
  • #16
using KE = 1/2mv^2

I find v by working backwards from my measured ranges.


If you aren't sure why the efficiency is constant, this discussion would seem pointless?
 
  • #17
donkeycopter said:
@rock.freak667: How is that relevant?

Because in that question, your formula for efficiency did not include the angle, it is a similar type of exercise.
 
  • #18
donkeycopter said:
but why does the angle not effect efficiency?

A leads to B leads to C ... Before you can get to why (or why not), answer my question first.

At what angle does air resistance act relative to the projectile's velocity? And at what angle does the projectile's velocity act relative to the launch angle? Are these angles constant, do they change, how so? When you change the launch angle, how do the other angles change? What does changing the launch angle do the time the projectile is in the air? How does that affect the amount of air resistance that acts on the projectile?
Go from there.
 
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  • #19
i am doing this experiment right now - literally

even though your teacher said it was correct, i don't think your way of calculating efficiency is the best. efficiency is the energy lost:

efficiency = (KE) / (EPE + GPE)

also
the angle does affect the efficiency. due to the different components, the angle affects the initial velocity and thus, the range. so the efficiency will change depending on the angle
 

FAQ: Does the Launch Angle Affect Efficiency in a Slingshot?

Why is efficiency important in scientific research?

Efficiency is important in scientific research because it allows scientists to achieve their goals and complete their experiments in a timely and cost-effective manner. It also ensures that resources, such as equipment and materials, are used efficiently and not wasted.

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Efficiency is considered to be constant because it is not affected by external factors and remains consistent regardless of the circumstances. This means that as long as the same methods and processes are used, the efficiency of an experiment should remain the same.

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