- #1
superpig10000
- 8
- 0
A pendulum consists of a mass m suspended by a massless spring with unextended length b and. spring constant k. Find Lagrange’s equations of motion
Here's how I set up my equation:
x = lsin(theta)
y = -lcos(theta)
(x=0 at equilibrium, y=0 at the point wehre the pendulum is hung from)
Kinetic energy = 1/2 * m * l^2 * (theta dot)^2
Potential energy = -mglcos(theta) + 1/2 kl^2
L = K - U
So after differentiating, I come up with:
theta double dot = w^2 sin (theta)
Does that look right to you?
I appreciate any help.
Here's how I set up my equation:
x = lsin(theta)
y = -lcos(theta)
(x=0 at equilibrium, y=0 at the point wehre the pendulum is hung from)
Kinetic energy = 1/2 * m * l^2 * (theta dot)^2
Potential energy = -mglcos(theta) + 1/2 kl^2
L = K - U
So after differentiating, I come up with:
theta double dot = w^2 sin (theta)
Does that look right to you?
I appreciate any help.