- #1
issacnewton
- 1,041
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Hello
I have some doubts about this problem which I have attached.
If we assume that both the clocks are started at the time the
airliner goes for a trip, then for an observer on the airliner,
when the airliner comes back to the New York, the time interval
would be a proper time interval since both the time measurements
are done at the same place on the airliner. But the
observer in New York is also not moving. So when the airliner
comes back and the observer in the ground stops his clock, his
measurement could also be considered proper time interval
since the measurement is again done at the same place.
Am I missing something ?
Thanks
[tex]\smile\smile\smile\smile[/tex]
I have some doubts about this problem which I have attached.
If we assume that both the clocks are started at the time the
airliner goes for a trip, then for an observer on the airliner,
when the airliner comes back to the New York, the time interval
would be a proper time interval since both the time measurements
are done at the same place on the airliner. But the
observer in New York is also not moving. So when the airliner
comes back and the observer in the ground stops his clock, his
measurement could also be considered proper time interval
since the measurement is again done at the same place.
Am I missing something ?
Thanks
[tex]\smile\smile\smile\smile[/tex]
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